Question

假设有两个活动A和B. A是登录活动，其中包含用户名，密码字段和登录按钮。输入用户名和密码并单击登录按钮后，它将进行网络呼叫。

如果我们要在同一个活动中测试它的视图，它将起作用（如果不是，我们可以使用自定义IdlingResource和管理）。

我想在登录过程完成后测试B活动。但是B活动也有一些网络呼叫（同时出现进度条）。所以直接onView()断言失败了。有没有一种标准的方法来实现这一目标？可以通过在Thread.sleep()断言之前添加onView()语句来实现，这是我不想做的。我该如何测试这种情况。

Answer 1

如果您的第二个活动已经完成了直观的操作标志，则可以使用以下解决方案：

创建界面：

/**
* Interface for expectations of compliance with the conditions.
*/
public interface Condition {
 /**
  * @return text description for log output when check failed.
 */
 String getDescription();

 /**
  * @return true if the condition is met.
  */
 boolean check();
}

并像这样使用它：

/**
* Wait while condition come true or timeout limit.
*
* @param condition condition for exit
* @param timeout   limit in seconds
* @throws Exception exception
*/
public static void waitForCondition(Condition condition, int timeout) throws Exception {
final int CONDITION_NOT_MET = 0;
final int CONDITION_MET = 1;
final int TIMEOUT = 2;

final int INTERVAL = 250;

int status = CONDITION_NOT_MET;
int elapsedTime = 0;

do {
  if (condition.check()) {
    status = CONDITION_MET;
  } else {
    elapsedTime += INTERVAL;
    delay(INTERVAL);
  }

  if (elapsedTime >= timeout * 1000) {
    status = TIMEOUT;
    break;
  }
} while (status != CONDITION_MET);

if (status == TIMEOUT) {
  String msg = condition.getDescription() + " - took more than " + timeout + " seconds. Test stopped.";
  log(msg);
  throw new Exception(msg);
 }
}

示例：

public class MovieScreenVisible implements Condition {
  @Override
  public String getDescription() {
    return "Movie screen should be on the top";
  }

  @Override
  public boolean check() {
    Activity activity = TestBase.getCurrentActivity();
    if (activity == null || !(activity instanceof MovieActivity)) {
      return false;
    }

    ViewGroup layout = activity.findViewById(R.id.movie_fragment);
    return layout != null && layout.getVisibility() == View.VISIBLE;
  }
}

// wait maximum 30 seconds until movie screen should be visible
waitForCondition(new MovieScreenVisible(), 30);

如何使用Android Espresso

1 个答案: