Question

我有一个oracle sql，我想用in子句获取一些数据。但我在语法的开头和结尾引用有错误。我不知道如何删除它。我用Google搜索并尝试更换，修剪但没有运气。有人可以帮我这个吗？以下是我的查询::

我当前提出错误的查询＆gt;＆gt;＆gt;

    SELECT CARE_TOPIC_ID, CARE_TOPIC_NAME, CREATED_BY, HISTORY_OF_ILLNESS, ASSESSMENT, PLAN FROM CARE_TOPIC_TEMPLATES 
  WHERE CARE_TOPIC_ID in ('1,2,3') ;

所需的查询应为＆gt;＆gt;

    SELECT CARE_TOPIC_ID, CARE_TOPIC_NAME, CREATED_BY, HISTORY_OF_ILLNESS, ASSESSMENT, PLAN FROM CARE_TOPIC_TEMPLATES 
  WHERE CARE_TOPIC_ID in (1,2,3) ;

Answer 1

如果CARE_TOPIC_ID的数据类型是文本，则正确用法为：

  SELECT CARE_TOPIC_ID, CARE_TOPIC_NAME, CREATED_BY, HISTORY_OF_ILLNESS, ASSESSMENT, PLAN FROM CARE_TOPIC_TEMPLATES WHERE CARE_TOPIC_ID in ('1','2','3') ;

否则如果是数字，则：

  SELECT CARE_TOPIC_ID, CARE_TOPIC_NAME, CREATED_BY, HISTORY_OF_ILLNESS, ASSESSMENT, PLAN FROM CARE_TOPIC_TEMPLATES WHERE CARE_TOPIC_ID in (1,2,3) ;

如何在oracle sql中替换开始和结束引用

1 个答案: