Question

我有以下HTML表单：

__invoke

将此表单提交给PHP时，我会这样做：

<input type="checkbox" name="markpaid[]">
<input name="paymentdate[]" value="$paymenttodaydate" type="text">

结果总是包含第一个数组。我想只获取$ paymentdate值，并选中相应的复选框。

任何提示？

由于

Answer 1

foreach($_POST['markpaid'] as $value) {
echo ($value);
}

如果::

，也可以在POST中尝试使用markpaid []

Answer 2

我最终得到了：

HTML

<input type="checkbox" name="markpaid[] value="$due->poreceivedid">
<input name="paymentdate-$due->poreceivedid" value="$paymenttodaydate" type="text">

PHP

$markpaid = $this->input->post('markpaid[]');
for ($i=0;$i<count($markpaid);$i++) {
   $paymentdate = $this->input->post('paymentdate-'.$markpaid[$i].'');
}

感谢@Epodax，@ abhishek-gurjar，@ ukhayp提示

Answer 3

从下方删除[]：

 $markpaid = $this->input->post('markpaid[]');
 $paymentdate = $this->input->post('paymentdate[]');

这将是：

 $markpaid = $this->input->post('markpaid');
 $paymentdate = $this->input->post('paymentdate');

现在$markpaid和$paymentdate将为您提供包含所选复选框值的数组。

<强> Reference

PHP表单复选框数组

3 个答案: