大多数连续登录日

Question

我们说我有这张桌子：

date        | has_login
------------------------
2015-01-01  | 1
2015-01-02  | 1
2015-01-03  | 0
2015-01-04  | 1
2015-01-05  | 1
2015-01-06  | 1
2015-01-07  | 0
2015-01-08  | 1

如何获得最多的连续登录？ 在这种情况下，它应该 3

Answer 1

试

select max(cons) as max_consecutives
from
(
    select @cons := case when has_login = 1 
                         then @cons + 1
                         else 1
                    end as cons
    from your_table
    cross join (select @cons := 0) c
    order by date
) tmp