想象一下,我有以下界面
interface IMarket {
ID: number,
Name: string,
MarketDescription: string
}
interface IDepartment {
ID: number,
Name: string,
DepartmentDescription: string
}
有没有办法将接口存储在这样的对象中?
var typeMap = { Markets: IMarket, Departments: IDepartment }
我想做这样的事情。我想基于我传递给构造函数的字符串值动态设置“getQueryResults”的泛型类型。
export class Service {
protected baseURL = "";
protected typeName = "";
private typeMap = { Markets: IMarket, Departments: IDepartment }
constructor(typeName) {
this.baseURL = 'http://localhost/API/odata/' + typeName;
this.currentType = typeMap[typeName];
}
getQueryResults(): Promise<this.currentType> {
return new Promise<this.currentType>((resolve, reject) => {
$.getJSON(this.baseURL, function (returnValue) {
resolve(returnValue.value);
});
})
}
}
var marketService = new Service("Markets");
var topMarket = marketService.getQueryResults();
//topMarket is an instance(?) of IMarket
var departmentService = new Service("Departments");
var topDepartment = departmentServicegetQueryResults();
//topDepartment is an instance(?) of IDepartment
答案 0 :(得分:1)
从TypeScript文档中记下:
http://www.typescriptlang.org/docs/handbook/namespaces.html#namespaced-validators
namespace Validation { export interface StringValidator { isAcceptable(s: string): boolean; }
看起来你想要:
namespace YourNamespace {
export interface IMarket {
ID: number,
Name: string,
MarketDescription: string
}
export interface IDepartment {
ID: number,
Name: string,
DepartmentDescription: string
}
}
答案 1 :(得分:1)
这可以使用generics简单地解决,它正是它的用途:
export class Service<T> {
protected baseURL = "";
constructor() {
this.baseURL = 'http://localhost/API/odata/' + typeName;
}
getQueryResults(): Promise<T> {
return new Promise<T>((resolve, reject) => {
$.getJSON(this.baseURL, function (returnValue) {
resolve(returnValue.value);
});
})
}
}
var marketService = new Service<IMarket>();
var topMarket: Promise<IMarket> = marketService.getQueryResults();
var departmentService = new Service<IDepartment>();
var topDepartment: Promise<IDepartment> = departmentService.getQueryResults();
你可以再使用2个类来“摆脱”多次Service<TYPE>
的需要(每个TYPE):
export abstract class Service<T> {
protected baseURL = "";
constructor() {
this.baseURL = 'http://localhost/API/odata/' + this.getTypeName();
}
getQueryResults(): Promise<T> {
return new Promise<T>((resolve, reject) => {
$.getJSON(this.baseURL, function (returnValue) {
resolve(returnValue.value);
});
})
}
protected abstract getTypeName(): string;
}
export class MarketsService extends Service<IMarket> {
protected getTypeName(): string {
return "Markets";
}
}
export class DepartmentsService extends Service<IDepartment> {
protected getTypeName(): string {
return "Departments";
}
}
var marketService = new MarketsService();
var topMarket: Promise<IMarket> = marketService.getQueryResults();
var departmentService = new DepartmentsService();
var topDepartment: Promise<IDepartment> = departmentService.getQueryResults();
但与每次使用Service
时指定类型的需要不同,这些额外的类将成为已编译的js的一部分,因此这是一个对您来说更重要的问题。