嵌套的Ajax调用无法看到其函数参数

时间:2016-06-23 22:08:38

标签: javascript jquery ajax promise

我正在运行ajax调用以检索令牌,然后一旦完成,我正在运行另一个ajax调用以命中特定端点。这全部包含在一个名为addAdmin的函数中,如下所示:

addAdmin: function(admin_data){

    console.log(admin_data) //returns an object

    // Get the access tolken
    var getAccessToken = $.ajax({
        type: "POST",
        url: 'http://somesite.com',
        data: d,
        contentType: 'application/json',
        success: function(response){
            console.log("Token success.")
        },
        error:function(jqXHR, textStatus, errorThrown) {
            console.log("request for token failed: ",jqXHR , textStatus, errorThrown);
        },
        dataType: 'json'
    });

    // when the ajax call is done (the token is received)
    getAccessToken.done(function(data) {

        console.log(admin_data) // returns undefined

        // hit the add endpoint url
        var downloadurl = $.ajax({
            type: "POST",
            url: "http://somesite.com/add",
            contentType: 'application/json',
            data: admin_data,
            success: function(response){
                ...
            },
            error:function(jqXHR, textStatus, errorThrown) {
                console.log("request for download url failed: ", textStatus, errorThrown, jqXHR);
            },
            dataType: 'json'
        })


     })

  },

问题是,我需要admin_data在第二个ajax调用中可见,但我无法弄清楚如何检索它,因为它超出了范围。这样做的推荐方法是什么?

1 个答案:

答案 0 :(得分:0)

使用ajax success函数的响应并将其作为参数/参数传递给您自己的函数:

success: function(response) {
    this.getAccessToken(response);
}

getAccessToken = function(response) {
    console.log(response);
    $.ajax({
        ...
        data: response,
        ...
    });
}
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