Question

我想计算在某些时段之间没有花费的时间。你可以把它想象成一个加班计算器。

输入是：

//This two is work start and end time.
$starttime="22:00";
$endtime="02:00";
//This two is person's entrance and exit time.
$entrance="2016-06-24 20:00:00"
$exit="2016-06-25 05:00:00"

在这种情况下，答案应该是5个小时。（可以在几秒钟内）

入口和出口时间可以更长（几天）或更短（同一天）。并且开始时间和结束时间可以在同一天。（例如：09：00-10：00）

我检查了this个问题，但如果时间段包含午夜，则代码无效。

谢谢你的回答。

Answer 1

如果您可以获得starttime和endtime的日期时间，则小功能getTimestampDiff将满足您的需求。

//This two is work start and end time.
$starttime = "2016-06-24 22:00";
$endtime   = "2016-06-25 02:00";
//This two is person's entrance and exit time.
$entrance = "2016-06-24 20:00:00";
$exit     = "2016-06-25 05:00:00";

function getTimestampDiff($startTime, $endTime)
{
    $start = new DateTime($startTime);
    $end   = new DateTime($endTime);

    return $end->getTimestamp() - $start->getTimestamp();
}

$timeIdle    = getTimestampDiff($starttime, $endtime);
$timeWorking = getTimestampDiff($entrance, $exit);

$res = ($timeWorking - $timeIdle);

echo sprintf("Time worked in minutes: %d<br />", $res / 60);
echo sprintf("Time worked in hours: %d", $res / 60 / 60);

输出：

Time worked in minutes: 300
Time worked in hours: 5

Answer 2

这里有一个代码，一个计算时间的代码，并且：

不使用任何非常低效且不需要的循环。

它计算能够准确处理任何小时的分钟数，例如14:27。

该代码处理午夜工作时间。

返回一个包含相关数据的精美数组，这对调试很有帮助。

结果在[＆＃39; total_in_minutes＆＃39;]中以分钟为单位，但也在[＆＃39; total_in_hours＆＃39;]中以小时为单位。

输出：

    Array
(
    [total_in_hours] => 5
    [total_in_minutes] => 300
    [days] => 1
    [is_over_midnight] => 1
    [total_min_first_day] => 120
    [total_min_middle_days] => 0
    [total_min_last_day] => 180
)

代码：

$starttime="22:00";
$endtime="02:00";
$entrance="2016-06-24 20:00:00";
$exit="2016-06-25 05:00:00";

$time = calc_overtime($starttime, $endtime, $entrance, $exit);
print_r($time);


function calc_overtime($starttime, $endtime, $entrance, $exit){

    $total_days = date("d", strtotime($exit)) - date("d", strtotime($entrance));
    $working_hours[0] = array('start'=>get_minutes($starttime), 'end'=>get_minutes($endtime));
    $working_hours_a_day = ($working_hours[0]['end']-$working_hours[0]['start']);
    $over_midnight = (get_minutes($endtime)<get_minutes($starttime))?1:0;

    // split into two working hours which end>start in both
    if ($over_midnight) {
        $working_hours[0] = array('start'=>get_minutes($starttime), 'end'=> 24*60);
        $working_hours[1] = array('start'=>0, 'end'=>get_minutes($endtime));
        $working_hours_a_day = ($working_hours[0]['end']-$working_hours[0]['start'])+($working_hours[1]['end']-$working_hours[1]['start']);
    }

    // only one day - came and left the same day
    if ($total_days == 0){
        $total_overtime = calc_overtime_one_day(get_minutes($exit)-get_minutes($entrance), get_minutes($entrance), get_minutes($exit), $working_hours[0]['start'], $working_hours[0]['end']);
        $total_overtime = $over_midnight? calc_overtime_one_day($total_overtime, get_minutes($entrance), get_minutes($exit), $working_hours[1]['start'], $working_hours[1]['end']): $total_overtime;
        return array('total_in_hours'=>$total_overtime/60 ,'total_in_minutes'=>$total_overtime ,  'days' => $total_days, 'is_over_midnight'=>$over_midnight) ;
    }

    // More than one day
    $total_overtime_first_day = calc_overtime_one_day(24*60-get_minutes($entrance), get_minutes($entrance), 24*60, $working_hours[0]['start'], $working_hours[0]['end']);
    $total_overtime_first_day = $over_midnight ? calc_overtime_one_day($total_overtime_first_day, get_minutes($entrance), 24*60, $working_hours[1]['start'], $working_hours[1]['end']): $total_overtime_first_day;

    $total_overtime_last_day = calc_overtime_one_day(get_minutes($exit)-0, 0, get_minutes($exit), $working_hours[0]['start'], $working_hours[0]['end']);
    $total_overtime_last_day = $over_midnight ? calc_overtime_one_day($total_overtime_last_day, 0, get_minutes($exit), $working_hours[1]['start'], $working_hours[1]['end']):$total_overtime_last_day;

    $total_middle_days = ($total_days>1)? ((24*60-$working_hours_a_day)*($total_days-1)):0;
    $total = $total_overtime_first_day + $total_overtime_last_day + $total_middle_days;

    return array('total_in_hours'=>$total/60 , 'total_in_minutes'=>$total ,
        'days' => $total_days, 'is_over_midnight'=>$over_midnight, 'total_min_first_day'=>$total_overtime_first_day,
        'total_min_middle_days'=>$total_middle_days, 'total_min_last_day'=>$total_overtime_last_day) ;
}


function calc_overtime_one_day($current_minutes, $entrance, $exit, $gap_start, $gap_end){
    if ($entrance>=$gap_end || $exit <= $gap_start) { return $current_minutes; }

    $remove_end   = $gap_end;
    $remove_start = $gap_start;

    if ($entrance>=$gap_start) { $remove_start = $entrance; }
    if ($exit<=$gap_end) {$remove_end = $exit;}


    if ($exit<=$gap_end) {$remove_end = $exit;}

    return $current_minutes - ($remove_end-$remove_start);
}


function get_minutes($string_time){
    $timestamp = strtotime($string_time);
    return 60*date("H", $timestamp)+1*date("i", $timestamp);
}

PHP发现时间没有花费在日期之间的特定时间段内

2 个答案: