使用swift

Question

我遇到了使用unarchiveObjectWithFile获得的数据的问题。我发送一本字典进行存档。我得到的数据显示调试时的值，但我无法从数据中提取密钥的确切值。总是得到零值

这是我的代码

class Person : NSObject, NSCoding {
struct Keys {
    static let Name = "name"
    static let Age = "age"
}

var name: [String] = []
var age: [Int] = []

init(dictionary: [String : AnyObject]) {
    name = dictionary[Keys.Name] as! [String]
    age = dictionary[Keys.Age] as! [Int]
}

func encodeWithCoder(archiver: NSCoder) {
    archiver.encodeObject(name, forKey: Keys.Name)
    archiver.encodeObject(age, forKey: Keys.Age)
}

required init(coder unarchiver: NSCoder) {

    if let namesList = unarchiver.decodeObjectForKey(Keys.Name) as? [String] {
        name = namesList
        print("name\(name)")
    }
    if let agesList = unarchiver.decodeObjectForKey(Keys.Age) as? [Int] {
        age = agesList
        print("age \(age)")
    }
    super.init()
}
}

// View controller 
class ViewController: UIViewController {
 override func viewDidLoad() {
    super.viewDidLoad()

    let persons: [String:AnyObject] = [
        "name" : ["a","b","c"],
        "age" : [2,3,4]
    ]

    let personObj = Person(dictionary: persons)
    NSKeyedArchiver.archiveRootObject(personObj, toFile: "/Users/shuvo/Desktop/Data.json")

    let responseObject = NSKeyedUnarchiver.unarchiveObjectWithFile("/Users/shuvo/Desktop/Data.json") as? Person

    if let unwrapData: AnyObject = responseObject {
        let nameArr = unwrapData["name"] as? [String]
        let ageArr = unwrapData["age"] as? [Int]
        print("age \(ageArr) name \(nameArr)")
    }
}

 override func didReceiveMemoryWarning() {
 super.didReceiveMemoryWarning()
 // Dispose of any resources that can be recreated.
   }
  }

Answer 1

那是因为您正在归档Person对象而不是[String: AnyObject]。

您可以归档Person，并将其解压缩为Person或归档[String: AnyObject]并提取该Person。你不能同时使用它们，因为它们是不同的类型。

如果您要归档NSCoding对象，请确保在Person课程中实施func encode(with aCoder: NSCoder) { aCoder.encode(name, forKey: "name") aCoder.encode(age, forKey: "age") } required init?(coder aDecoder: NSCoder) { self.name = aDecoder.decodeObject(forKey: "name") as! [String] self.age = aDecoder.decodeObject(forKey: "age") as! [Int] } 协议并与此类似...

if let responseObject = NSKeyedUnarchiver.unarchiveObject(withFile: path) as? Person {
    // You can use `responseObject` as a `Person` object here... 
}

之后，你可以做......

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