我正在尝试使用多个条件构造IF语句,但是我无法使用此PHP代码获得echo“TRUE”。
<?php
$totalDays = 4;
$startDateL = 'Friday';
$endDateL = 'Monday';
$pickupTime = '12:00:00';
$returnTime = '9:00:00';
if($totalDays == 4 AND
$pickupTime == '12:00:00' AND
$returnTime == '09:00:00' AND
$startDateL == 'Friday' AND
$endDateL == 'Monday') {
echo 'TRUE';
}
?>
答案 0 :(得分:0)
您的var ran = [];
var qan = 4;
for(i=0;i<(qan);i++){
rd = Math.floor(Math.random()*360);
ran.push(rd);
};
for(i=0;i<10;i++){
/*need to have (random.length) number of console logs and interval loops by 1 second*/
console.log((ran[0]+i) + " loop " + (i));
console.log((ran[1]+i) + " loop " + (i));
console.log((ran[2]+i) + " loop " + (i));
console.log((ran[3]+i) + " loop " + (i));
};
是'9:00:00',但是在您的情况下将其与'09:00:00'进行比较。
答案 1 :(得分:0)
您输错了,请参阅评论。
$totalDays = 4;
$pickupTime = '12:00:00';
$returnTime = '09:00:00'; // I cnanged this time
$startDateL = 'Friday';
$endDateL = 'Monday';
if (($totalDays == 4) AND
($pickupTime == '12:00:00') AND
($returnTime == '09:00:00') AND
($startDateL == 'Friday') AND
($endDateL == 'Monday'))
{
echo 'TRUE';
}
else echo 'FALSE';
答案 2 :(得分:0)
<?php
$totalDays = 4;
$startDateL = 'Friday';
$endDateL = 'Monday';
$pickupTime = '12:00:00';
$returnTime = '09:00:00'; //<== MAKE SURE THE FORMATS ARE THE SAME '09:00:00' NOT '9:00:00'
if($totalDays == 4 AND
$pickupTime == '12:00:00' AND
$returnTime == '09:00:00' AND
$startDateL == 'Friday' AND
$endDateL == 'Monday') {
echo 'TRUE';
}