将Google链接打开到新标签页

时间:2016-06-28 10:22:35

标签: java selenium

我想将Google搜索结果打开到新标签中。我试过这段代码:

WebDriver driver = new ChromeDriver();
        driver.get("http://www.google.com/xhtml");
        Thread.sleep(5000);
        WebElement searchBox = driver.findElement(By.name("q"));
        searchBox.sendKeys("ChromeDriver");
        searchBox.submit();

        System.out.println("Current Url: " + driver.getCurrentUrl());

        WebDriverWait wait = new WebDriverWait(driver, 10);
        wait.until(ExpectedConditions.presenceOfElementLocated(By.cssSelector("h3.r a")));

        List<WebElement> results = driver.findElements(By.xpath("//h3[@class='r']/a"));

        for (int i = 0; i < results.size(); i++)
        {
            String selectLinkOpeninNewTab = Keys.chord(Keys.CONTROL,Keys.RETURN);
            driver.findElement(By.xpath("//h3[@class='r']/a")).sendKeys(selectLinkOpeninNewTab);

            System.out.println("Google result " + results.get(i).getText());
        }

到目前为止,代码会打开空标签并打印搜索结果的名称。我如何打开searh结果中的链接?

2 个答案:

答案 0 :(得分:1)

只需更改loop内的以下行: -

driver.findElement(By.xpath("//h3[@class='r']/a")).sendKeys(selectLinkOpeninNew‌​Tab);

results.get(i).sendKeys(selectLinkOpeninNewTab);

它的工作......:)

答案 1 :(得分:1)

试试此代码

System.setProperty("webdriver.chrome.driver", "D:/WorkSpace/Driver/chromedriver.exe");
        WebDriver driver = new ChromeDriver();

        driver.get("http://www.google.com/xhtml");
        Thread.sleep(5000);
        WebElement searchBox = driver.findElement(By.name("q"));
        searchBox.sendKeys("ChromeDriver");
        searchBox.submit();

        System.out.println("Current Url: " + driver.getCurrentUrl());

        WebDriverWait wait = new WebDriverWait(driver, 10);
        wait.until(ExpectedConditions.presenceOfElementLocated(By.cssSelector("h3.r a")));

        List<WebElement> results = driver.findElements(By.xpath("//h3[@class='r']/a"));

        for (WebElement ele : results) {
            String selectLinkOpeninNewTab = Keys.chord(Keys.CONTROL, Keys.RETURN);
            ele.sendKeys(selectLinkOpeninNewTab);


        }