Question

我有SuperClass实施<UIWebViewDelegate>，在本课程中我实施了方法webView:shouldStartLoadWithRequest:navigationType:

@interface SuperClass
...
- (BOOL)webView:(UIWebView *)webView shouldStartLoadWithRequest:(NSURLRequest *)request1 navigationType:(UIWebViewNavigationType)navigationType {
     // SuperClass treatment
}
...
@end

然后我有SubClass扩展此SuperClass。 SubClass也实现<UIWebViewDelegate>，方法webView:shouldStartLoadWithRequest:navigationType:也是如此：

@interface SubClass: SuperClass
...
- (BOOL)webView:(UIWebView *)webView shouldStartLoadWithRequest:(NSURLRequest *)request1 navigationType:(UIWebViewNavigationType)navigationType {
     // SubClass treatment
}
...
@end

该代码适用于我，因为我需要对SubClass进行特定处理。但在特定情况下，我需要调用SuperClass webView:shouldStartLoadWithRequest:navigationType:方法。

我需要代理人执行SuperClass UIWebViewDelegate方法。

我尝试使用super来调用SuperClass方法，但没有用！

这可能吗？

Answer 1

<强>父类

@interface ViewController () <UIWebViewDelegate>
@end

@implementation ViewController

- (BOOL)webView:(UIWebView *)webView shouldStartLoadWithRequest:(NSURLRequest *)request1 navigationType:(UIWebViewNavigationType)navigationType 
{    
  NSLog(@"superview");
  return true;    
}

子类（ViewController1.m）

@interface ViewController1 () <UIWebViewDelegate>

@property (strong, nonatomic) IBOutlet UIWebView *webview;

@end

@implementation ViewController1

- (BOOL)webView:(UIWebView *)webView shouldStartLoadWithRequest:(NSURLRequest *)request1 navigationType:(UIWebViewNavigationType)navigationType {

     NSLog(@"subclass");
     [super webView:webView shouldStartLoadWithRequest:request1 navigationType:navigationType];
     return true;

 }

- (IBAction)action:(id)sender {

    NSLog(@"loading");
    [_webview loadRequest:[NSURLRequest requestWithURL:[NSURL URLWithString:@"http://www.google.co.in"]]];

 }

在日志中它将作为：

2016-06-29 17：51：39.807测试[31575：8224563] loading

2016-06-29 17:51:41.008测试[31575：8224563]子类

2016-06-29 17:51:41.008测试[31575：8224563] superview

Answer 2

@interface SuperClass
- (void)handleWebViewShouldStartLoadWithRequest:(NSURLRequest *)request;

- (BOOL)webView:(UIWebView *)webView shouldStartLoadWithRequest:(NSURLRequest *)request navigationType:(UIWebViewNavigationType)navigationType {
     [self handleWebViewShouldStartLoadWithRequest:request];
}

@end

在子类的handleWebViewShouldStartLoadWithRequest:中，您可以调用[super handleWebViewShouldStartLoadWithRequest:request];

如何从SubClass委托方法调用SuperClass委托方法

2 个答案: