我有以下SQL Server查询:
select flujo, FECHA from El_Bosque
where fecha between CONVERT(DATETIME,'2016-06-22 10:00:00',102)
and CONVERT(DATETIME,'2016-06-28 00:00:00',102) and ( flujo >=0 )
order by fecha asc
它返回:
0.84 2016-06-22 10:00:00.000
0.84 2016-06-22 10:00:00.000
0.83 2016-06-22 10:15:00.000
0.83 2016-06-22 10:15:00.000
0.81 2016-06-22 10:30:00.000
0.81 2016-06-22 10:30:00.000
我想过滤此查询,因此我只能获得不同的行:
0.84 2016-06-22 10:00:00.000
0.83 2016-06-22 10:15:00.000
0.81 2016-06-22 10:30:00.000
提前谢谢。
答案 0 :(得分:0)
DISTINCT
关键字可用于仅返回不同(不同)的值。
SELECT DISTINCT column_name,column_name
FROM table_name;
所以你的SQL查询看起来像
select DISTINCT flujo, FECHA from El_Bosque
where fecha between CONVERT(DATETIME,'2016-06-22 10:00:00',102)
and CONVERT(DATETIME,'2016-06-28 00:00:00',102) and ( flujo >=0 )
order by fecha asc
答案 1 :(得分:-1)
尝试使用不同的关键字
select
DISTINCT -- this keyword
flujo, FECHA from El_Bosque
where fecha between CONVERT(DATETIME,'2016-06-22 10:00:00',102)
and CONVERT(DATETIME,'2016-06-28 00:00:00',102) and ( flujo >=0 )
order by fecha asc
另请注意,您的查询使用CONVERT函数,您可以通过编写
来改善DECLARE @t1 datetime
DECLARE @t2 datetime
SELECT @t1=CONVERT(DATETIME,'2016-06-22 10:00:00',102) , @t2=CONVERT(DATETIME,'2016-06-28 10:00:00',102)
select
DISTINCT -- this keyword
flujo, FECHA from El_Bosque
where fecha between @t1 and @t2 and ( flujo >=0 )
order by fecha asc