我有一个内容包含在由c.cpp:26: error: template parameter 'typename std::enable_if<(! std::is_fundamental::value), int>::type <anonymous>'
c.cpp:36: error: redeclared here as 'typename std::enable_if<std::is_fundamental::value, int>::type <anonymous>'
生成的div中。有可能内容为null它只生成了什么，但我想隐藏包装内容的div。
我已经完成了将它放在一个循环中，一旦我声明the_content它不起作用或变量的声明正在生成它，尽管我的主要观点是将值存储到该函数。以下是我的所作所为。
$pageContent这是什么行不通。
<div id="content" class="clearfix row">
<div id="main" class="col col-md-12 clearfix" role="main">
<?php if ( have_posts() ) {
while ( have_posts() ) {
the_post();
the_content();
$thispage=$post->ID;
}
} ?>
<div class="page-header"><h1><?php the_title(); ?></h1></div>
<?php $childpages = query_posts('orderby=menu_order&order=asc&post_type=page&post_parent='.$thispage);
if($childpages){
echo '<div class="page-content">';
foreach ($childpages as $post) :
setup_postdata($post); ?>
<article id="post-<?php the_ID(); ?>" <?php post_class('clearfix'); ?> role="article">
<h2><?php the_title(); ?></h2>
<div class="page-image img-responsive"><?php the_post_thumbnail(full);?></div>
<?php
if ($pageContent->the_content != '') {
echo '<div class="page-content">'.$pageContent.'</div>'; }
}
?>
</article>
<?php
endforeach;
echo '</div>';
} ?>
</div>
</div>
通常我会用这个替换代码才能工作。即使在内容的空状态下也会生成div。
<?php
if ($pageContent->the_content != '') {
echo '<div class="page-content">'.$pageContent.'</div>'; }
}
?>
这也有效，我觉得应该是错的。 $ <div class="page-content"><?php the_content();?></div>
正在生成内容而不是if条件。
pageContent = the_content();答案 0 :(得分：1)
你是对的，the_content()回应内容而不是回复它。阅读WordPress manual。你会找到源代码：
function the_content( $more_link_text = null, $strip_teaser = false) {
$content = get_the_content( $more_link_text, $strip_teaser );
/**
* Filter the post content.
*
* @since 0.71
*
* @param string $content Content of the current post.
*/
$content = apply_filters( 'the_content', $content );
$content = str_replace( ']]>', ']]>', $content );
echo $content;
}
如您所见，它会输出内容。您可以使用get_the_content()来检查是否有。然后输出您的<div>或您想要的内容，拨打the_content()，然后输出</div>。不要试图将the_content连接成一个字符串。
您可能还希望将get_the_content()存储到变量中并应用过滤器，并在if块中自行替换字符串。
答案 1 :(得分：0)
如果/**
* Created by Ninan John J P on 6/30/2016.
*/
import java.util.Scanner;
public class JavaApplication62 {
public static void main(String[] args) {
while (true) {
Scanner in = new Scanner(System.in);
System.out.println("1.Enroll Student");
System.out.println("2.Offer Course");
//String name = in.next(); Not required. This will want a text input before proceeding further.
int choice = in.nextInt();
if (choice == 1) {
student_class[] studentList = new student_class[500];
studentList[0] = new student_class();
while (true) {
System.out.print(" Enter name of the student: ");
studentList[0].setName(in.next());
System.out.println("");
System.out.print(" The student is given the unique ID = " + studentList[0].getUniqueStudentID() + " and the number of students = " + studentList[0].getNumberOfStudents());
/* System.out.print("> and the number of students : ");
//studentList[0].setnumberOfStudents(in.nextInt);
studentList[0].setNumberOfStudents(in.nextInt());
*/ //This is not required. You have already done this in the previous print statment.
System.out.println("");
System.out.print(" Enter the e-mail address of the student: ");
//studentList[0].setemail(in.next); you are calling the wrong method. Also in.next should be a method.
studentList[0].setEmail(in.next());
System.out.print("Enter the semester number of the student: ");
// studentList[0].setsemesterNumber(in.nextInt); // same as prev error
studentList[0].setSemesterNumber(in.nextInt());
System.out.print(" Add another student (Y/N): ");
char add = in.next().charAt(0);
if (add == 'Y' || add == 'y') {
}
if (add == 'N' || add == 'n') {
break;
}
}
} else if (choice == 2) {
while (true) {
Course[] courseOfferedList;
courseOfferedList = new Course[500];
courseOfferedList[0] = new Course();
System.out.println("Enter the course code : ");
//courseOfferedList[0].setCourseCode(in.next()); // next() returns a string. You need nextInt() here.
courseOfferedList[0].setCourseCode(in.nextInt());
System.out.println(" Enter the course title: ");
courseOfferedList[0].setCourseTitl(in.next());
System.out.println(" Enter the credit hours of the course: ");
courseOfferedList[0].setCreditHours(in.nextInt());
System.out.print(" Add another course (Y/N): ");
char add2 = in.next().charAt(0);
// if (add2 == 'Y' || add2 == 'y') { // not needed
// }
if (add2 == 'N' || add2 == 'n') {
break;
}
}
}
}
}
}
生成内容，为什么不用它来检查呢
所以而不是
the_content()尝试以下代码
<?php
if ($pageContent->the_content != '') {
echo '<div class="page-content">'.$pageContent.'</div>';
}
?>
答案 2 :(得分：0)
你可以在下面添加它运行的PHP代码。
<?xml version="1.0" encoding="utf-8"?>
<android.support.v4.widget.DrawerLayout
xmlns:android="http://schemas.android.com/apk/res/android"
xmlns:app="http://schemas.android.com/apk/res-auto"
xmlns:tools="http://schemas.android.com/tools"
android:id="@+id/drawer_layout"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:fitsSystemWindows="true"
tools:context=".MainActivity"
android:elevation="7dp">
<include
layout="@layout/app_bar_get_sensors"
android:layout_width="match_parent"
android:layout_height="match_parent" />
<android.support.design.widget.NavigationView
android:id="@+id/nav_view"
android:layout_width="wrap_content"
android:layout_height="match_parent"
android:layout_gravity="start"
android:fitsSystemWindows="true"
/>
</android.support.v4.widget.DrawerLayout>
答案 3 :(得分：0)
使用此代码，这将对您有用。
<?php if(the_content() ) { ?>
<div class="page-content">
<?php the_content();?>
</div>
<?php } else{
echo "div not showing";
} ?>