如何填写下拉列表表单数据库表?

时间:2016-06-30 05:03:43

标签: c# asp.net database

如何使用对控制器的ajax调用从数据库表填充下拉列表?我试过这个。

AJAX致电

public static Shelf<ShelfItems> GetDropDown()
        {
            string query = "SELECT StoreID";
            string constr = ConfigurationManager.ConnectionStrings["constr"].ConnectionString;
            using (SqlConnection con = new SqlConnection(constr))
            {
                using (SqlCommand cmd = new SqlCommand(query))
                {
                    List<ListItem> customers = new List<ListItem>();
                    cmd.CommandType = CommandType.Text;
                    cmd.Connection = con;
                    con.Open();
                    using (SqlDataReader sdr = cmd.ExecuteReader())
                    {
                        while (sdr.Read())
                        {
                            customers.Add(new ListItem
                            {
                                Value = sdr["CustomerId"].ToString(),
                                Text = sdr["Name"].ToString()
                            });
                        }
                    }
                    con.Close();

                }
            }
             return customers;
        }

控制器代码:

   public class Shelf
        {
            public string StoreID { get; set; }
            public string ShelfName { get; set; }
            public string MinTemperature { get; set; }
            public string MaxTemperature { get; set; }
        }    

型号:

for (int idx = 0; idx < total_row_student; idx++)

3 个答案:

答案 0 :(得分:1)

使用此:在Html中:

      $.ajax({
                        type: "GET",
                        url: '@Url.Action("AllCustomer", "Customers")',
                        contentType: "application/json;charset=utf-8",
                        data: JSON.stringify(),
                        dataType: "json",
                        success: function(data) {
                            $('#customers').empty().append('<option value="">---Select---</option>');
                            $.each(data, function(index, value) {
                                $('#customers').append($('<option />', {
                                    value: value.Id,
                                    text: value.Name
                                }));
                            });
                        },
                    });

行动中:

public ActionResult AllCustomer()
{
  return Json(db.Customers.ToList(), JsonRequestBehavior.AllowGet);
}

现在按照自己的方式进行编辑

答案 1 :(得分:1)

    $.ajax({
        type: "GET",
        url: '/ControllerName/ActionName',
        success: function (data) {
            $('#customers').empty().append('<option value="">--Select---</option>');
            $.each(data, function (index, value) {
                $('#customers').append($('<option />', {
                    text: value.StoreID
                }));
            });
        },
    });

在控制器

    public virtual JsonResult GetDropDown()
    {
        string query = "SELECT StoreID";
        string constr = ConfigurationManager.ConnectionStrings["constr"].ConnectionString;
        List<ListItem> customers = new List<ListItem>();
        using (SqlConnection con = new SqlConnection(constr))
        {
            using (SqlCommand cmd = new SqlCommand(query))
            {

                cmd.CommandType = CommandType.Text;
                cmd.Connection = con;
                con.Open();
                using (SqlDataReader sdr = cmd.ExecuteReader())
                {
                    while (sdr.Read())
                    {
                        customers.Add(new ListItem
                        {
                            Value = sdr["CustomerId"].ToString(),
                            Text = sdr["Name"].ToString()
                        });
                    }
                }
                con.Close();

            }
        }
        return Json(customers, JsonRequestBehavior.AllowGet);
    }

答案 2 :(得分:1)

将您的选择查询更正为

    var position: CGFloat = 0.0

    for urlString in (stringURLArray).reverse()  {
        let imageView1 = UIImageView(frame: CGRectMake(0 + position, 0, 200, 50))
        let url = NSURL(string: urlString) //
        let data = NSData(contentsOfURL: url!)
        imageView1.image = UIImage(data: data!)
        self.view.addSubview(imageView1)
        position += 200 // space out the width of each image
    }
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