Question

我正在使用以下代码通过ajax发送表单

<script>
$(document).ready(function(){

    $("#update-settings").submit(function(e) {

        var url = "files/jquery-pages/page_jquery_settings.php"; // the script where you handle the form input.

        $.ajax({
            type: "POST",
            url: url,
            data: $("#update-settings").serialize(), // serializes the form's elements.
            success: function(data)
            {
                $("#success-settings").hide().html(data).fadeIn('slow');
            }
        });
        e.preventDefault(); // avoid to execute the actual submit of the form.
    });

});
</script>

<div id="success-settings"></div>

到目前为止这个工作正常。

我的php页面像这样：

<?php               
    if(isset($_POST['change_password']) == $settings_btn_change_password) 
    {       
        echo "The password has been changed";   
    }

    if(isset($_POST['update_email']) == $settings_btn_update_email) 
    {       
        echo "This is email update";
    }
?>

以下是表格：

<form method="post" action="" name="update-settings" id="update-settings">
    <div class="row">
        <div class="col-md-12">
            <input type="submit" value="<?php echo $settings_btn_change_password;?>" name="change_password" class="button_blue_standard pull-right">
        </div>
    </div>

    <div class="row">
        <div class="col-md-12">
            <input type="submit" value="<?php echo $settings_btn_update_email;?>" name="update_email" class="button_blue_standard pull-right">
        </div>
    </div>
</form>

问题是，当我点击提交按钮更改密码示例时，它显示“密码已更改”和“这是电子邮件更新”。

如果我按下该按钮，我只想显示“密码已被更改”。

任何想法为什么？

Cheerz :)

Answer 1

isset无法与==一起使用。所以请这样使用。

<?php
   if(isset($_POST['change_password'])) 
    {    
        echo "The password has been changed";
    }

    if(isset($_POST['update_email'])) 
    {  
        echo "This is email update";
    }

?>

Answer 2

试试这个

<?php
   if((isset($_POST['change_password'])) && ($settings_btn_change_password==$_POST['change_password'])) 
    {  
        echo "The password has been changed";
    }
    if((isset($_POST['update_email'])) && ($settings_btn_update_email==$_POST['update_email'])) 
    {  
        echo "This is email update";
    }
?>

我希望它会有所帮助

Answer 3

请使用＆＃39;退出;＆＃39;在每个echo语句之后。所以它应该是这样的： -

<?php
    if(isset($_POST['change_password']) == $settings_btn_change_password) 
    {       
        echo "The password has been changed";
        exit;
    }

    if(isset($_POST['update_email']) == $settings_btn_update_email) 
    {       
        echo "This is email update";
        exit;
    }
?>

Answer 4

我在工作，所以我没有时间测试这个，但尝试：

if(isset($_POST['change_password']) && $_POST['change_password'] == $settings_btn_change_password) {
    echo "The password has been changed";
    exit();
} else if(isset($_POST['update_email']) && $_POST['update_email'] == $settings_btn_update_email) {
    echo "This is an email update";
    exit();
} else {
    echo "Action not successfully carried out, try again";
    error_log("There's an issue here, check it out"); 
}

提交ajax表单显示所有php isset语句

4 个答案: