Question

需要一些帮助，我想在prodprice表中加总价格并将其添加到prodcost表中的a_cost，b_cost和c_cost，其中main_item是00002在prodcomb中，00002的secondary_item是00001，现在是0000 in prodbm在main_item中有2个secondary_item 00005和00006这两个价格在prodprice中，我想在那里加价并加上a_cost，b_cost和c_cost。

结果如下所示，unitprice由a_cost + b_cost + c_cost + sumprice组成。

+-----+-----------+
| qty | unitprice |
+-----+-----------+
| 2   | 23.50     |
+-----+-----------+

prodprice

+-------+------+
| item  | price| 
+-------+------+
| 00005 | 5.00 |
+-------+------+
| 00006 | 3.50 |
+-------+------+

prodbm

+-----------+----------------+
| main_item | secondary_item |
+-----------+----------------+
| 00001     | 00005          |
+-----------+----------------+
| 00001     | 00006          |
+-----------+----------------+

prodcomb

+-----------+----------------+-----+
| main_item | secondary_item | qty |
+-----------+----------------+-----+
| 00002     | 00001          | 2   |
+-----------+----------------+-----+

prodcost

+-------+--------+--------+--------+-------+
| item  | a_cost | b_cost | c_cost | m_cost|
+-------+--------+--------+--------+-------+
| 00001 | 5      | 5      | 5      | 6     |
+-------+--------+--------+--------+-------+

提前谢谢。

Answer 1

应该是

for path in ('some_path/rest//','some_path/rest\\','some_path/rest','some_path/rest/','some_path/rest\\'):
    print path + ' -> ' + re.sub(r"some_path[\\\\/]+rest(?:([\\\\/])(?=\1))?", 'FILTER', path)

如何总结然后加起来到另一列

1 个答案: