替换特定字符后的特定字符序列

Question

我有下面的字符串，例如：

O > O §o TEXT §r §o TEXT §r

我需要在§r字符之后将所有 §r§a替换为> 。

应该是

O > O §o TEXT §r§a §o TEXT §r§a

结果。

我尝试了＆gt; *（\§r）正则表达式，但忽略了＆gt; 。

你可以指出我的错误吗？

Answer 1

最简单的方法是首先将其拆分为两个字符串，然后运行replace。也就是说，你可以采取

int index = inputString.indexOf('>') + 1;
String first = inputString.subString(0, index);
String second = inputString.subString(index);
String finalString = first + second.replace("§r", "§r§a");

使用纯正则表达式执行此操作将非常困难。

Answer 2

描述

((?:(?!>).)*>.*?|)(§r)

替换为： $1§r§a

_{**要更好地查看图像，只需右键单击图像并在新窗口中选择视图}

实施例

现场演示

https://regex101.com/r/xP8dI5/1

示例文字

§r O > O §o TEXT §r §o TEXT §r

重播后

§r O > O §o TEXT §r§a §o TEXT §r§a

解释

NODE                     EXPLANATION
----------------------------------------------------------------------
  (                        group and capture to \1:
----------------------------------------------------------------------
    (?:                      group, but do not capture (0 or more
                             times (matching the most amount
                             possible)):
----------------------------------------------------------------------
      (?!                      look ahead to see if there is not:
----------------------------------------------------------------------
        >                        '>'
----------------------------------------------------------------------
      )                        end of look-ahead
----------------------------------------------------------------------
      .                        any character except \n
----------------------------------------------------------------------
    )*                       end of grouping
----------------------------------------------------------------------
    >                        '>'
----------------------------------------------------------------------
    .*?                      any character except \n (0 or more times
                             (matching the least amount possible))
----------------------------------------------------------------------
   |                        OR
----------------------------------------------------------------------
  )                        end of \1
----------------------------------------------------------------------
  (                        group and capture to \2:
----------------------------------------------------------------------
    §r                      '§r'
----------------------------------------------------------------------
  )                        end of \2
----------------------------------------------------------------------

Answer 3

纯正则表达式方法是使用\G，如下面的

(\G(?!\A)|>)(.*?)§r

，并替换为

$1$2§r§a

<强> Regex Demo

Java代码

System.out.println("O§r §r > O §o TEXT §r §o §r TEXT §r".replaceAll("(\\G(?!\\A)|>)(.*?)§r", "$1$2§r§a"));

<强> Ideone Demo