我可以从odoo中的自定义模块继承吗？

Question

我的odoo中有自定义模块，名为＆＃34; x_vehicles＆＃34;

是否可以从此模块继承以覆盖create方法??

我有这段代码

class extend_vehicle(models.Model):
    _inherit = 'x_vehicle'

    @api.model
    def create(self, vals):

        # Do something...

        return super(extend_vehicle, self).write(vals)

但是我收到了这个错误

2016-07-04 15:05:20,488 9217 ERROR pro werkzeug: Error on request:
Traceback (most recent call last):
  File "/Users/jose/Work/odoo/env/lib/python2.7/site-packages/werkzeug/serving.py", line 177, in run_wsgi
    execute(self.server.app)
  File "/Users/jose/Work/odoo/env/lib/python2.7/site-packages/werkzeug/serving.py", line 165, in execute
    application_iter = app(environ, start_response)
  File "/Users/jose/Work/odoo/openerp/service/server.py", line 246, in app
    return self.app(e, s)
  File "/Users/jose/Work/odoo/openerp/service/wsgi_server.py", line 184, in application
    return application_unproxied(environ, start_response)
  File "/Users/jose/Work/odoo/openerp/service/wsgi_server.py", line 170, in application_unproxied
    result = handler(environ, start_response)
  File "/Users/jose/Work/odoo/openerp/http.py", line 1493, in __call__
    return self.dispatch(environ, start_response)
  File "/Users/jose/Work/odoo/openerp/http.py", line 1467, in __call__
    return self.app(environ, start_wrapped)
  File "/Users/jose/Work/odoo/env/lib/python2.7/site-packages/werkzeug/wsgi.py", line 588, in __call__
    return self.app(environ, start_response)
  File "/Users/jose/Work/odoo/openerp/http.py", line 1642, in dispatch
    ir_http = request.registry['ir.http']
  File "/Users/jose/Work/odoo/openerp/http.py", line 363, in registry
    return openerp.modules.registry.RegistryManager.get(self.db) if self.db else None
  File "/Users/jose/Work/odoo/openerp/modules/registry.py", line 355, in get
    update_module)
  File "/Users/jose/Work/odoo/openerp/modules/registry.py", line 386, in new
    openerp.modules.load_modules(registry._db, force_demo, status, update_module)
  File "/Users/jose/Work/odoo/openerp/modules/loading.py", line 334, in load_modules
    force, status, report, loaded_modules, update_module)
  File "/Users/jose/Work/odoo/openerp/modules/loading.py", line 237, in load_marked_modules
    loaded, processed = load_module_graph(cr, graph, progressdict, report=report, skip_modules=loaded_modules, perform_checks=perform_checks)
  File "/Users/jose/Work/odoo/openerp/modules/loading.py", line 132, in load_module_graph
    models = registry.load(cr, package)
  File "/Users/jose/Work/odoo/openerp/modules/registry.py", line 169, in load
    model = cls._build_model(self, cr)
  File "/Users/jose/Work/odoo/openerp/models.py", line 591, in _build_model
    original_module = pool[name]._original_module if name in parents else cls._module
  File "/Users/jose/Work/odoo/openerp/modules/registry.py", line 84, in __getitem__
    return self.models[model_name]
KeyError: 'x_vehicle'

我不知道我是否需要从其他模特扩展或做一些特别的事情......

拜托，有人可以帮助我吗？

编辑：可能使用名称＆＃34;自定义模块＆＃34;我犯了一个错误...... 它是在odoo内部构建的模块，而不是外部模块。我没有模块的代码。它是用odoo提供的工具构建的。

我无法提取结构，因为它有点复杂提取所有功能，因此，我需要尝试从该模块继承

我希望这可能更具体

编辑2：我认为这是问题所在...... 如果我尝试安装继承该功能的模块，请在选项卡＆＃34;技术数据＆＃34;我可以看到模型是未知的......但我不知道为什么......

此外，这是我的实际 openerp .py文件

{
    ...
    'category': 'Automation',
    'version': '1',
    # any module necessary for this one to work correctly
    'depends': ['base','x_vehicle'],
    # always loaded
    'data': [

    ]
}

Answer 1

是的，这是可能的。

打开__openerp__.py文件并使用以下密钥进行更新

"depends" : [
    'base', 'list_of_core_module', 'your_custom_module_name'
],

其中

list_of_core_module 如销售，购买，帐户等......，

your_custom_module_name 您已声明 x_vehicles 类

在您处理时重新启动服务器并升级当前模块。