我搜索了很多,我知道这个问题已被多次询问,但是找不到合适的解决方案。
我有一个具有以下结构的课程
namespace Website.Models
{
public class DynamicControlModel
{
}
public class QuestionnairModel
{
public long QuestionId { get; set; }
public string Question { get; set; }
public List<QuestionnairOptionModel> QuestionnairOption { get; set; }
}
public class QuestionnairOptionModel
{
public long OptionId { get; set; }
public string OptionString { get; set; }
public bool OptionControl1 { get; set; }
public string OptionControl2 { get; set; }
}
}
我尝试这样做:
public ActionResult ProcessRequest(List<QuestionnairModel> model)
{
List<QuestionnairModel> result = new List<QuestionnairModel>(model);
result = result.Where(x => x.QuestionnairOption.Any(l => l.OptionControl1 == true)).ToList();
result.ForEach(x => x.QuestionnairOption.RemoveAll(m => m.OptionControl1 == false));
return View(@"~\Views\Home\About.cshtml", model);
}
这里的问题是,当我从结果对象中删除项目时,它也会从模型中删除。我希望模型对象不会因结果对象的任何变化而受到影响。
我知道class默认是通过引用传递的,这就是它从对象中删除的原因。
让我知道如何通过可以解决问题的价值来传递它。
答案 0 :(得分:1)
不应该:https://msdn.microsoft.com/en-us/library/fkbw11z0.aspx
但是。 尝试在List result = new List(model)之前克隆原始列表;
答案 1 :(得分:0)
感谢@David Pilkington
我已使用以下代码解决了我的问题。
public static class ObjectCopier { /// /// Perform a deep Copy of the object. /// /// The type of object being copied. /// The object instance to copy. /// The copied object. public static T Clone(T source) { if (!typeof(T).IsSerializable) { throw new ArgumentException("The type must be serializable.", "source"); } // Don't serialize a null object, simply return the default for that object if (Object.ReferenceEquals(source, null)) { return default(T); } IFormatter formatter = new BinaryFormatter(); Stream stream = new MemoryStream(); using (stream) { formatter.Serialize(stream, source); stream.Seek(0, SeekOrigin.Begin); return (T)formatter.Deserialize(stream); } } }
我在现有代码中所做的唯一更改是将[Serializable]属性添加到我的类中。
[Serializable] public class QuestionnairModel { public long QuestionId { get; set; } public string Question { get; set; } public List QuestionnairOption { get; set; } } [Serializable] public class QuestionnairOptionModel { public long OptionId { get; set; } public string OptionString { get; set; } public bool OptionControl1 { get; set; } public string OptionControl2 { get; set; } }
答案 2 :(得分:0)
将列表作为参考类型遍历。
您需要再次创建
List<QuestionnairModel> result = new List<QuestionnairModel>(
model.Select(m => new QuestionnairModel()
{
Question = m.Question,
QuestionId = m.QuestionId,
QuestionnairOption = new List<QuestionnairOptionModel>(
m.QuestionnairOption.Select(n => new QuestionnairOptionModel()
{
OptionId = n.OptionId,
OptionString = n.OptionString,
OptionControl1 = n.OptionControl1,
OptionControl2 = n.OptionControl2
}).ToList()
)
}).ToList()
);
完整功能
public ActionResult ProcessRequest(List<QuestionnairModel> model)
{
List<QuestionnairModel> result = new List<QuestionnairModel>(
model.Select(m => new QuestionnairModel()
{
Question = m.Question,
QuestionId = m.QuestionId,
QuestionnairOption = new List<QuestionnairOptionModel>(
m.QuestionnairOption.Select(n => new QuestionnairOptionModel()
{
OptionId = n.OptionId,
OptionString = n.OptionString,
OptionControl1 = n.OptionControl1,
OptionControl2 = n.OptionControl2
}).ToList()
)
}).ToList()
);
result = result.Where(x => x.QuestionnairOption.Any(l => l.OptionControl1 == true)).ToList();
result.ForEach(x => x.QuestionnairOption.RemoveAll(m => m.OptionControl1 == false));
return View(@"~\Views\Home\About.cshtml", model);
}
现在,它会从 result
中删除该项目,而不是 model
。