Question

像这样调用UDF：

SELECT
       product_name,
       SUM(quantity) AS SumQty,
       SUM(face_value) AS SumFaceValue,
       SUM(net_cost)AS SumNetCost,
       SUM(face_value - net_cost) AS SumScripRebate,
       organization_name
FROM getSalesSummary(@GLSCOrgId, @BeginDate, @EndDate) getSalesSummary
GROUP BY product_name, organization_name
ORDER BY product_name

产量：

   "Chili's      1    25.00   22.75  2.25   Sample Organization 1
    CVS/pharmacy 1  25.00   23.50  1.50   Sample Organization 1
    Macy's       1  100.00  90.00  10.00  Sample Organization 1"

使用UDF逻辑并使用SELECT测试结果：

SELECT 
       product_name,
       SUM(quantity) AS SumQty,
       SUM(face_value) AS SumFaceValue,
       SUM(net_cost) AS SumNetCost,
       SUM(face_value - net_cost) AS SumScripRebate,
       organization_name
FROM @ReturnTable
GROUP BY product_name, organization_name
ORDER BY product_name

产量：

   "Chili's       4   100.00  91.00   9.00   Sample Organization 1
    CVS/pharmacy  1   25.00   23.50   1.50   Sample Organization 1
    Macy's        1   100.00  90.00   10.00  Sample Organization 1"

@ReturnTable是UDF返回的表，其创建方式如下：

INSERT INTO @ReturnTable(product_name,
                         unit_price,
                         quantity,
                         face_value,
                         net_cost,
                         organization_name)
(select * from @TablePartial UNION select * from @TableClosed)

使用SELECT和变量的测试返回正确的数据，但调用UDF并没有获得其他3个Chili的记录。我使用相同的数据参数。我对UDF很新，我不确定为什么它会返回与SELECT不同的数据。有任何建议和/或答案吗？

Answer 1

您可能需要UNION ALL而不是UNION

查看两个结果集，它加起来好像4个Chilli的行都是一样的。

Chili's      1    25.00   22.75  2.25   Sample Organization 1
Chili's      1    25.00   22.75  2.25   Sample Organization 1
Chili's      1    25.00   22.75  2.25   Sample Organization 1
Chili's      1    25.00   22.75  2.25   Sample Organization 1
-------------------------------------------------------------
Chili's       4   100.00  91.00   9.00   Sample Organization 1

使用UNION将删除重复项，只留下一行。

Answer 2

我唯一能想到的是UNION将其更改为UNION ALL UNION将消除重复

运行这些查询以查看差异

select 1 as a
union 
select 1
union 
select 1


select 1 as a
union  all
select 1
union all
select 1

TVF UDF不会返回与SELECT相同的数据

2 个答案: