Question

如果我的CLOB字段包含用逗号分隔的多个值，并且需要将它们合计以获得最终输出，那么我如何在SQL Developer中实现它？

示例表：

STOCK | COST

ABCDE | 258.40,299.50
FGHIJ | 100.50,70.50,95.30

我希望能够选择每一行的总数。

ABCDE希望选择总计557.90

对于FGHIJ来说，总共选择266.30

Answer 1

如果您使用的是Oracle 12，则可以使用LATERAL：

select t.stock, sum(to_number(p.cst,'9999999.9999')) total
 from table_name t,
 lateral (select regexp_substr(t.cost,'[^,]+', 1, level) cst from dual
          connect by regexp_substr(t.cost, '[^,]+', 1, level) is not null) p
group by t.stock

否则：

select stock, sum(cst) total
 from (
        select stock,to_number(column_value,'9999999.9999') cst
       from  table_name t, xmltable(('"'|| REPLACE(t.cost, ',', '","')|| '"'))        
      ) p
group by stock

Answer 2

这是使用CTE（公用表表达式）和处理NULL列表元素的正则表达式的方法（或在查询中显式忽略它们，SUM无论如何都忽略它们）：

SQL> -- First build the base table.
SQL> with tbl(stk, cst) as (
     select 'ABCDE', ',258.40,299.50'       from dual union
     select 'FGHIJ', '100.50,70.50,,,95.30' from dual
   ),
   -- Turn the list into a table using the comma as the delimiter. Think of it
   -- like a temp table in memory. This regex format handles NULL list elements.
   example_tbl(stock, cost) as (
     select stk, regexp_substr(cst, '(.*?)(,|$)', 1, level, NULL, 1)
     from tbl
     connect by regexp_substr(cst, '(.*?)(,|$)', 1, level) is not null
     group by stk, level, cst
   )
   -- select * from example_tbl;
   SELECT stock, to_char(sum(cost), '9990.99') Total
   from example_tbl
   group by stock;

STOCK TOTAL
----- --------
ABCDE   557.90
FGHIJ   266.30

SQL>

在一列中添加多个值以逗号分隔

2 个答案: