Question

我正在尝试发送JSON对象，但结果却发送了一个解析错误。

{"readyState":4,"responseText":"","status":200,"statusText":"OK"}

这是代码

var data = {
  fb_id: response.id,
  email: response.email,
  name: response.name,
  first_name: response.first_name,
  last_name: response.last_name,
  verified: response.verified,
  birthday:response.birthday,
  picture: response.picture.data.url,
  hometown: response.hometown.name,
  gender: response.gender 
};
$.ajax({
  url:'connect.php',
  type: 'POST',
  data: {
    user: data
  },
  dataType: 'JSON',
  success: function(html){
    //page();
    console.log(JSON.stringify(data));
  },
  error: function(XMLHttpRequest, textStatus, errorThrown) {
    if (XMLHttpRequest.readyState == 4) {
      console.log(JSON.stringify(XMLHttpRequest));
    }
  }

}）;

后端在这里： JSON对象正在这里发送

if(isset($_POST['user'])) {
  //convert json object to php associative array
  $data = $_POST['user'];
  $fbid = $data['fb_id'];             // To Get Facebook ID
  $fbfullname = $data['name']; // To Get Facebook full name
  $femail = $data['email'];    // To Get Facebook email ID
  $fbname = $data['first_name'];
  $fblname = $data['last_name'];
  $fbgender = $data['gender'];
  $fverified = $data['verified'];
  $faddress = $data['hometown'];
  $fbirth = $data['birthday'];
  $img = $data['picture'];

}

对象正在发送类似的内容：

{
    "fb_id":"xxxxxxxxxxx99",

    "email":"sxxxxxx@xxx.in",

    "name":"Sagar xxxx",
    ...
}

PS：我使用的是jquery.min.js的1.12.4版本

更新当我尝试使用此查询向connect.php页面发送请求时，它在控制台日志中返回错误。如果我将dataType更改为＆＃34; text＆＃34;或者排除它然后它不会返回任何错误但是connect.php无法识别使用ajax请求发布的任何查询，即isset（$ _ POST [＆＃39; user＆＃39;]）将无法识别任何疑问。

Answer 1

我不是PHP专家，但问题可能是您将JSON作为帖子正文发送，而后端则以urlencoded格式运行。我想你需要从请求中获取一个普通的json，将其解析为一个数组，然后进行处理。您可以在Issue reading HTTP request body from a JSON POST in PHP

找到有用的示例

同时将dataType更改为“application / json”

Answer 2

在你的php脚本中，在阅读json后添加此代码：

  if(isset($_POST['user']))
  {
 //convert json object to php associative array
  $data = $_POST['user'];
  $fbid = $data['fb_id'];            // To Get Facebook ID
  $fbfullname = $data['name']; // To Get Facebook full name
  $femail = $data['email'];    // To Get Facebook email ID
  $fbname = $data['first_name'];
  $fblname = $data['last_name'];
  $fbgender = $data['gender'];
  $fverified = $data['verified'];
  $faddress = $data['hometown'];
  $fbirth = $data['birthday'];
  $img = $data['picture'];

添加此代码：

  header("Content-Type: application/json", true); 

  /* Return JSON */
  echo json_encode("Success");

  /* Stop Execution */
  exit;

}

“成功”文字在onSuccess(html)

中发送

JSON解析错误响应＆＃34; status＆＃34;：200，＆＃34; statusText＆＃34;：＆＃34; OK＆＃34;

2 个答案: