Question

我有很多模式想要在许多字符串数组中找到匹配的字符串，并将其替换为＆＃34; NON＆＃34;串。例如，如果我们有：

str[0]={"this","is","a simple","text","for","example","."};
str[1]={"Can","you","help me","please","?","thank","you","very much"};
string[] patterns={"the","that","(eg width)","123",",","text","for example","help me","very much"};

将str [i]中的匹配模式替换为＆＃34; NON＆＃34;是欲望的结果：

str[0]={"this","is","a simple","NON","NON","NON","."};
str[1]={"Can","you","NON","please","?","thank","you","NON"};`

我该怎么做？

感谢。

Answer 1

如果你想要一个变异的解决方案：

public void ReplaceStrs(string[] srcStrs, string[] patterns, string changeTo)
{
    for (int i=0; i < srcStrs; i++) {
        if (Array.IndexOf(patterns, toChange[i]) >= 0) {
            srcStrs[i] = changeTo;
        }
    }
}

非不同诱变：

public string[] ReplaceStrs(string[] srcStrs, string[] patterns, string changeTo) {
     srcStrs.Select(s => Array.IndexOf(patterns, s) >= 0 ? changeTo : s).ToArray();
}

Answer 2

只是为了好玩的一个班轮：]

str = Array.ConvertAll(str, a => Array.ConvertAll(a, i => patterns.Contains(i) ? "NON" : i));

如何使用regexp查找字符串中的模式？

2 个答案: