Question

我有以下输入

<?xml version="1.0" encoding="UTF-8"?>
    <Input>
     <Userlist>
       <name>ABC</name>
       <division>1</division>
    <method>online</method>
    <subject>M</subject>
    <fee>10k</fee>
    </Userlist>
    <Userlist>
       <name>BCD</name>
       <division>2</division>
    <method>Distance</method>
    <fee>5k</fee>
    <subject>C</subject>
    </Userlist>
    <Userlist>
       <name>CDF</name>
       <division>2</division>
    <method>Direct</method>
    <fee>15k</fee>
    <subject>P</subject>
    </Userlist>
    <Userlist>
       <name>FGH</name>
       <division>55</division>
    <method>Direct</method>
    <fee>25k</fee>
    <subject>E</subject>
    </Userlist>
    <Userlist>
       <name>HKM</name>
       <division>55</division>
    <method>Direct</method>
    <fee>40k</fee>
    <subject>H</subject>
    </Userlist>
    </Input>

以下是预期输出：要求是，基于方法值（那些是预定义值）循环通过它们，如果超过出现，我们需要将相对值放在过滤器下。如果我们有相同的分区，内部过滤器也属于下面的一个细节元素。我甚至无法放置代码，因为它没有给出更近的代码。感谢您的帮助。

<?xml version="1.0" encoding="UTF-8"?>
<Output>
 <AllUserslist>
  <User>
  <Methodtype>online</Methodtype>
  <Filters>
<Filter>
<Section>1</Section>
<Details>
<Detail>
<Studentname>ABC</Studentname>
<Fee>10k</Fee>
<subject>M</subject>
</Detail>
</Details>
</Filter>
</Filters>
</User>
 <User>
  <Methodtype>Distance</Methodtype>
  <Filters>
<Filter>
<Section>2</Section>
<Details>
<Detail>
<Studentname>BCD</Studentname>
<Fee>5k</Fee>
<subject>C</subject>
</Detail>
</Details>
</Filter>
</Filters>
</User>
 <User>
 <Methodtype>Direct</Methodtype>
<Filters>
<Filter>
<Section>2</Section>
<Details>
<Detail>
<Studentname>CDF</Studentname>
<Fee>15K</Fee>
<subject>P</subject>
</Detail>
</Details>
</Filter>
<Filter>
<Section>55</Section>
<Details>
<Detail>
<Studentname>FGH</Studentname>
<Fee>25K</Fee>
<subject>E</subject>
</Detail>
<Detail>
<Studentname>HKM</Studentname>
<Fee>40K</Fee>
<subject>H</subject>
</Detail>
</Details>
</Filter>
</Filters>
 </User>
 </AllUserslist>
 </Output>

Answer 1

以这种方式试试吗？

XSLT 1.0

<xsl:stylesheet version="1.0" 
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>

<xsl:key name="group-method" match="Userlist" use="method" />
<xsl:key name="group-division" match="Userlist" use="concat(method, '|', division)" />

<xsl:template match="/Input">
    <Output>
        <AllUserslist>
            <xsl:for-each select="Userlist[generate-id() = generate-id(key('group-method', method)[1])]">
                <User>
                    <Methodtype><xsl:value-of select="method"/></Methodtype> 
                    <Filters>
                        <xsl:for-each select="key('group-method', method)[generate-id() = generate-id(key('group-division', concat(method, '|', division))[1])]">
                            <Filter>
                                <Section><xsl:value-of select="current()/division"/></Section>
                                <Details>
                                    <xsl:for-each select="key('group-division', concat(method, '|', division))">
                                        <Detail>
                                            <Studentname><xsl:value-of select="name"/></Studentname>
                                            <Fee><xsl:value-of select="fee"/></Fee>
                                            <subject><xsl:value-of select="subject"/></subject>
                                        </Detail>
                                        </xsl:for-each>
                                </Details>
                            </Filter>       
                        </xsl:for-each> 
                    </Filters>   
                </User> 
            </xsl:for-each>    
        </AllUserslist> 
    </Output>  
</xsl:template>

</xsl:stylesheet>

Answer 2

假设您可以使用XSLT 2.0，您可以使用两个嵌套for-each-group group-by来解决它：

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
    xmlns:xs="http://www.w3.org/2001/XMLSchema" exclude-result-prefixes="xs" version="2.0">

    <xsl:output indent="yes"/>

    <xsl:template match="@* | node()">
        <xsl:copy>
            <xsl:apply-templates select="@* | node()"></xsl:apply-templates>
        </xsl:copy>
    </xsl:template>

    <xsl:template match="Input">
        <Output>
            <AllUserslist>
                <xsl:for-each-group select="Userlist" group-by="method">
                    <User>
                        <Methodtype>
                            <xsl:value-of select="current-grouping-key()"/>
                        </Methodtype>
                        <Filters>
                            <xsl:for-each-group select="current-group()" group-by="division">
                                <Filter>
                                    <Section>
                                        <xsl:value-of select="current-grouping-key()"/>
                                    </Section>
                                    <Details>
                                        <xsl:apply-templates select="current-group()"/>
                                    </Details>
                                </Filter>
                            </xsl:for-each-group>
                        </Filters>
                    </User>
                </xsl:for-each-group>
            </AllUserslist>
        </Output>
    </xsl:template>

    <xsl:template match="Userlist">
        <Detail>
            <xsl:apply-templates select="* except (method, division)"/>
        </Detail>
    </xsl:template>

    <xsl:template match="name">
        <Studentname>
            <xsl:value-of select="."/>
        </Studentname>
    </xsl:template>

    <xsl:template match="fee">
        <Fee>
            <xsl:value-of select="."/>
        </Fee>
    </xsl:template>
</xsl:stylesheet>

必需的转换xslt代码

2 个答案: