Question

如何使用以下查询使用laravel eloquent执行where子句：

public class MyFragmentTest {

    @Rule
    public FragmentTestRule<MyFragment> mFragmentTestRule = new FragmentTestRule<>(MyFragment.class);

    @Test
    public void fragment_can_be_instantiated() {

        // Launch the activity to make the fragment visible 
        mFragmentTestRule.launchActivity(null);

        // Then use Espresso to test the Fragment
        onView(withId(R.id.an_id_in_the_fragment)).check(matches(isDisplayed()));
    }
}

我不知道如何为此修改此代码：

select * from stats where payed = 1 AND WHERE (user_id = 1 OR owner_id = 1)

Answer 1

像这样改变

$payouts = Stat::where('payed', '1');
        $payouts->where(function ($payouts) {
            $payouts->where('owner_id', Auth::user()->id)
                  ->orWhere('user_id', Auth::user()->id);
        })->get();

Answer 2

试试这个

 $payouts = Stat::where('payed', '1')
            ->where(function ($query) {
              $query->where('owner_id', Auth::user()->id)
                        ->orwhere('user_id', Auth::user()->id);
             })->get();

Answer 3

你很接近，这应该可以解决问题：

$payouts = Stat::where('payed', '1')
            ->where(function ($query) {
                $query->where('owner_id', Auth::user()->id)
                      ->orWhere('user_id', Auth::user()->id);
            })->get();

这是在寻找where payed = 1 AND (owner_id is the current user ID OR the user_id is the current user ID)

laravel 5.2嵌套Where子句

3 个答案: