需要更改网址以搜索引擎友好

Question

浪费了3天来解决问题。有一个网址http://wordporn.com/open-quote-img/id:712528/需要更改open-quote-img / -text-from-quote /

有一个文件opens_quote.mld.php 页面http://wordporn.com/open-quote-img/id:712528/的代码，但无法理解如何从链接生成页面

$ID = (int) CURRENT_ID;
    if(!$ID) { setNextPage(404); }
    else {          
            $Quotes = $this->MySql->getSqlTor();
            $Quotes->Select(TB_QUOTES,'q');
            $Quotes->LeftJoin(TB_QUOTES_AUTORS,array('id'=>'`q`.autor'),'qa');
            $Quotes->Fields(array('id','text','slug','likes','updated'));
            $Quotes->Fields(array(
                'url' =>'autor_link',
                'name'=>'autor_name',
                'img' =>'autor_img'
            ),'qa');
            $Quotes->Condition('id',$ID);
            $Quotes->Order('likes','>','q');
            $Quotes->Range($this->inPage);
            $Quotes = (array) $Quotes->GetOne();

core.php中的

有这个：

private $RezervedUrl = array(
    'action'=>'/^do_([0-9a-zA-Z]+)$/',
    'page'=>'/^page:([0-9]{0,4})$/',
    'id'=>'/^id:([0-9a-zA-Z-]+)$/',);

和此：

define('CURRENT_ID',(isset($this->RezervedUrl['id']))?$this->RezervedUrl['id']:false);