重新格式化DateTime数组

时间:2016-07-18 17:43:48

标签: scala jodatime

我使用jodatime

使用以下代码生成了一个日期数组
import org.joda.time.{DateTime, Period}
import org.joda.time.format.DateTimeFormat
import java.text.SimpleDateFormat


def dateRange(from: DateTime, to: DateTime, step: Period): Iterator[DateTime] 
=Iterator.iterate(from)(_.plus(step)).takeWhile(!_.isAfter(to))

val from = new DateTime(2000, 06, 30,0,0,0,0)
val to = new DateTime(2001, 06, 30,0,0,0,0)
val by = new Period(0,2,0,0,0,0,0,0)

val range = { dateRange(from ,to, by)}

val dateRaw = (range).toArray

如何将DateTimeFormat.forPattern("YYYYMMdd")传递给每个值以获取格式为yyyyMMdd的整数数组

Array [Int] = Array(20000630,20000830,20001030 ......

1 个答案:

答案 0 :(得分:1)

val f = DateTimeFormat.forPattern("YYYYMMdd")
dateRaw.map(d => f.print(d).toInt)
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