无法以编程方式将故事板中的现有子视图添加到视图中

时间:2016-07-19 10:07:53

标签: ios swift uiview uiscrollview swift2

我试图在代码中模拟这个视图层次结构:

 "scene"
    "view Shop Main"                       -> `UIView`
        "view shop scroll"                 -> `UIScrollView`
            "ViewDetail"                   -> `UIView`
                "Shop Connected Container" -> `UIView`
                    "Connected Shop"       -> `UIView`

我想实例化倍数" Connected Shop"并将它们添加到" Shop Connected Container" 像这样:

"scene"
    "view Shop Main"                       -> `UIView`
        "view shop scroll"                 -> `UIScrollView`
            "ViewDetail"                   -> `UIView`
                "Shop Connected Container" -> `UIView`
                    "Connected Shop"       -> `UIView`
                    "Connected Shop"       -> `UIView`
                    "Connected Shop"       -> `UIView`

我怎么能以编程方式执行此操作? 我有一个每个subView的自定义类和一个xib文件。 这就是我如何从代码中实例化子视图:

  override func viewDidLoad() {

  /*1*/         let vShopMain = NSBundle.mainBundle().loadNibNamed("viewShopMain", owner: self, options: nil).first as! viewShopMain
    /*2*/       let vShopScroll = NSBundle.mainBundle().loadNibNamed("viewShopScroll", owner: vShopMain, options: nil).first as! viewShopScroll

    /*3*/       let vDetail : UIView = NSBundle.mainBundle().loadNibNamed("viewDetail", owner: vShopScroll, options: nil).first as! viewDetail
//
//
    /*4*/       let sConContainer : UIView = NSBundle.mainBundle().loadNibNamed("shopConnectedContainer", owner: vDetail, options: nil).first as! shopConnectedContainer
   /*5*/        let cShop = NSBundle.mainBundle().loadNibNamed("connectedShop", owner: sConContainer, options: nil).first as! connectedShop


        cShop.bannerTitle.text = "Shop Title"

        vShopMain.addSubview(vShopScroll)
        vShopScroll.addSubview(vDetail)
        vDetail.addSubview(sConContainer)
        sConContainer.addSubview(cShop)


        self.view.addSubview(sConContainer)

也尝试了完全相同的结果:

        let vShopMain = UINib(nibName: "viewShopMain", bundle: nil).instantiateWithOwner(nil, options: nil)[0] as! viewShopMain

       let scroll = UINib(nibName: "viewShopScroll", bundle: nil).instantiateWithOwner(nil, options: nil)[0] as! viewShopScroll

        let vDetail = UINib(nibName: "viewDetail", bundle: nil).instantiateWithOwner(nil, options: nil)[0] as! viewDetail

        let sConContainer = UINib(nibName: "shopConnectedContainer", bundle: nil).instantiateWithOwner(nil, options: nil)[0] as! shopConnectedContainer

        let cShop = UINib(nibName: "connectedShop", bundle: nil).instantiateWithOwner(nil, options: nil)[0] as! connectedShop

        cShop.bannerTitle.text = "hola"

        vShopMain.addSubview(scroll)
        scroll.addSubview(vDetail)
        vDetail.addSubview(sConContainer)
        sConContainer.addSubview(cShop)


        self.view.addSubview(sConContainer)

但"新"添加的视图位于另一个视图下方,这不是预期的行为,因为我从故事板中实例化现有视图,而不是创建新视图。

我遵循故事板层次结构的顺序。视图也与其自定义类链接,并且它们具有xib文件。但是,当我运行我的应用程序时,我遇到了这个奇怪的问题

我在这里做错了什么?请帮忙

1 个答案:

答案 0 :(得分:0)

帮助您找出崩溃的原因。 loadNibNamed返回一个对象数组,而不是单个视图。所以这肯定会崩溃

let vShopScroll = NSBundle.mainBundle().loadNibNamed("viewShopScroll", owner: self, options: nil) as! viewShopScroll  

因为你假设它返回viewShopScroll并强行打开它。正如你所说,你的第一行正在运行,因为你在那里采用了first对象

let vShopMain = NSBundle.mainBundle().loadNibNamed("viewShopMain", owner: self, options: nil).first as! viewShopMain

同样适用于所有其他案例

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