Question

我有三个相关的表“users”，“category”和“interest_area”;我想将表单中的数据插入“users”表，然后从“category”表中选择另一个数据，并使用PHP插入“interest_area”表。

显示的错误是：

错误：INSERT INTO用户（user_id，first_name，last_name，higher_education，user_name，pass_word）VALUES（＆＃39;＆＃39;＆＃39; 87878787＆＃39;，＆＃39; iuiu＆＃39;，＆＃39; iuiu＆＃39;，＆＃39; root＆＃39;＆＃39;＆＃39;）; INSERT INTO interest_area（category_id）SELECT category_id FROM category WHERE category_name =＆＃39; ASP＆＃39 ;; Erreur desyntaxepr�sde＆＃39; INSERT INTO interest_area（category_id）SELECT category_id FROM category＆＃39; �la ligne 2

我的PHP代码是：

<?php
   if (isset($_POST["interest_area"])){             
   $f_name = $_POST["firstname"];
   $l_name = $_POST["last_name"];
   $h_education = $_POST["higher_education"];
   $i_area = $_POST["interest_area"];
   $email = $_POST["email"];
   $u_name = $_POST["user_name"];
   $p_word = $_POST["pass_word"];

  $sql = "INSERT INTO users(user_id, first_name, last_name,   higher_education, user_name, pass_word)
  VALUES('' , '$f_name' , '$l_name' , '$h_education' , '$username' ,  '$password');";

  $sql .= "INSERT INTO interest_area (category_id)
    SELECT category_id FROM category
    WHERE category_name = '$i_area';";

if ($conn->query($sql) === TRUE) {
echo "New record created successfully";} 
else { echo "Error: " . $sql . "<br>" . $conn->error;} 
}
?>

Answer 1

你必须运行两个mysqli_query才能插入

mysqli_query

在插入数据时更好地使用prepare语句

prepare statement

$f_name = $_POST["firstname"];
$l_name = $_POST["last_name"];
$h_education = $_POST["higher_education"];
$i_area = $_POST["interest_area"];
$email = $_POST["email"];
$u_name = $_POST["user_name"];
$p_word = $_POST["pass_word"];
$user_id = $_POST["user_id"];

$user_id如果是主键则不应为空，则无法插入数据;

 $sql1 = "INSERT INTO users(user_id, first_name, last_name,   higher_education, user_name, pass_word)
      VALUES('$user_id' , '$f_name' , '$l_name' , '$h_education' , '$u_name' ,  '$p_word')";

 $sql2 = "INSERT INTO interest_area (category_id)
     SELECT category_id FROM category WHERE category_name = '$i_area'";

 mysqli_query($con,$sql1);
 mysqli_query($con,$sql2) 
 mysqli_close($con);

Answer 2

您只需将两个INSERT语句作为单独的$conn->query调用运行，而不是将它们连接成一个调用。

Answer 3

语法错误在这里：

$sql .= "INSERT INTO interest_area (category_id)
SELECT category_id FROM category
WHERE category_name = '$i_area';";

应该卷曲......

$sql .= "INSERT INTO interest_area (category_id)
SELECT category_id FROM category
WHERE category_name = {$i_area};";

如上所述两个单独的查询...

Answer 4

您需要将multi_query用于多个查询。

$sql = "INSERT INTO users(user_id, first_name, last_name, higher_education, user_name, pass_word)VALUES('' , '$f_name' , '$l_name' , '$h_education' , '$username' , '$password');";

$sql .= "INSERT INTO interest_area (category_id)
     SELECT category_id FROM category WHERE category_name = '$i_area'";

 mysqli_multi_query($con,$sql);
 mysqli_close($con);

我想将表单中的数据插入表中，然后从另一个表中选择另一个数据并使用PHP插入第三个表

4 个答案: