我有两个多级Series，并希望根据这两个索引合并它们。第一个Series看起来像这样：
# of restaurants
BORO CUISINE
BRONX American 425
Chinese 330
Pizza 206
BROOKLYN American 1254
Chinese 750
Cafe/Coffee/Tea 350
第二个有更多行，就像这样：
# of votes
BORO CUISINE
BRONX American 2425
Caribbean 320
Chinese 3130
Pizza 3336
BROOKLYN American 21254
Caribbean 2320
Chinese 7250
Cafe/Coffee/Tea 3350
Pizza 13336
答案 0 :(得分：2)
设定：
s1 = pd.Series({('BRONX', 'American'): 425, ('BROOKLYN', 'Chinese'): 750, ('BROOKLYN', 'Cafe/Coffee/Tea'): 350, ('BRONX', 'Pizza'): 206, ('BROOKLYN', 'American'): 1254, ('BRONX', 'Chinese'): 330})
s2 = pd.Series({('BRONX', 'Caribbean'): 320, ('BRONX', 'American'): 2425, ('BROOKLYN', 'Chinese'): 7250, ('BROOKLYN', 'Cafe/Coffee/Tea'): 3350, ('BRONX', 'Pizza'): 3336, ('BROOKLYN', 'American'): 21254, ('BROOKLYN', 'Pizza'): 13336, ('BRONX', 'Chinese'): 3130, ('BROOKLYN', 'Caribbean'): 2320})
s1 = s1.rename_axis(['BORO','CUISINE']).rename('restaurants')
s2 = s2.rename_axis(['BORO','CUISINE']).rename('votes')
print (s1)
BORO CUISINE
BRONX American 425
Chinese 330
Pizza 206
BROOKLYN American 1254
Chinese 750
Cafe/Coffee/Tea 350
Name: restaurants, dtype: int64
print (s2)
BORO CUISINE
BRONX American 2425
Caribbean 320
Chinese 3130
Pizza 3336
BROOKLYN American 21254
Caribbean 2320
Chinese 7250
Cafe/Coffee/Tea 3350
Pizza 13336
Name: votes, dtype: int64
如果需要join，请使用concat参数inner join：
print (pd.concat([s1,s2], axis=1, join='inner'))
restaurants votes
BORO CUISINE
BRONX American 425 2425
Chinese 330 3130
Pizza 206 3336
BROOKLYN American 1254 21254
Cafe/Coffee/Tea 350 3350
Chinese 750 7250
#join='outer' is by default, so can be omited
print (pd.concat([s1,s2], axis=1))
restaurants votes
BORO CUISINE
BRONX American 425.0 2425
Caribbean NaN 320
Chinese 330.0 3130
Pizza 206.0 3336
BROOKLYN American 1254.0 21254
Cafe/Coffee/Tea 350.0 3350
Caribbean NaN 2320
Chinese 750.0 7250
Pizza NaN 13336
另一种解决方案是merge使用reset_index：
#by default how='inner', so can be omited
print (pd.merge(s1.reset_index(), s2.reset_index(), on=['BORO','CUISINE']))
BORO CUISINE restaurants votes
0 BRONX American 425 2425
1 BRONX Chinese 330 3130
2 BRONX Pizza 206 3336
3 BROOKLYN American 1254 21254
4 BROOKLYN Chinese 750 7250
5 BROOKLYN Cafe/Coffee/Tea 350 3350
#outer join
print (pd.merge(s1.reset_index(), s2.reset_index(), on=['BORO','CUISINE'], how='outer'))
BORO CUISINE restaurants votes
0 BRONX American 425.0 2425
1 BRONX Chinese 330.0 3130
2 BRONX Pizza 206.0 3336
3 BROOKLYN American 1254.0 21254
4 BROOKLYN Chinese 750.0 7250
5 BROOKLYN Cafe/Coffee/Tea 350.0 3350
6 BRONX Caribbean NaN 320
7 BROOKLYN Caribbean NaN 2320
8 BROOKLYN Pizza NaN 13336