仅在逗号分隔文件中删除引号之间的逗号

Question

这是我的意见：

"a","b","c","d","","f"

预期产出：

","

基本上每发生一次""，我都想用SELECT faq.faq_id , faq.title , faq.status , fv.metadesc , fv.metakey , fv.metakey , faq.url_key FROM faq INNER JOIN (SELECT faq_id, MAX(IF(attribute = 'metadesc',value,null)) metadesc, MAX(IF(attribute = 'metakey',value,null)) metakey, MAX(IF(attribute = 'meta_image', value, null)) meta_image FROM faq_value GROUP BY faq_id) fv ON fv.faq_id = faq.faq_id 替换它。 另外，我想为 n 字段数量的 n 行运行命令。

我已尝试过以下命令

awk -F＆＃39;＆＃34;＆＃39; -v OFS =＆＃39;＆＃39; ＆＃39; {for（i = 2; i＆lt; = NF; i + = 2）gsub（＆＃34;，＆＃34;，＆＃34;＆＃34;，$ i）} 1＆＃39; infile中

但它也删除了双引号，但这不是我要求的...... 我还需要双引号

Answer 1

你可以试试这个

echo '"a","b","c","d",",","f"'  | sed 's/,",",/,"",/g'

Answer 2

也许这有效：

echo '"a","b","c","d",",","f"' | awk '{sub(/\42,\42,\42/,"\42,\42\42")}1'
"a","b","c","d","","f"