Question

我有以下字符串：

Name_Location_Telephone_break_Name_Location_Telephone_break_Name_Location_Telephone_break_Name_Location_Telephone_break_

我是使用DOM从HTML页面的cURL获得的。

我的最终结果必须是JSON文件，如：

!important

但我知道首先我必须拆分字符串，我试过这个

Shop 1: { name: "example", location: "example", telephone: "0123"}
Shop 2: { name: "example", location: "example", telephone: "0123"}

但它不起作用。有人能帮助我吗？

Answer 1

你正在爆炸错误的价值：

Name_Location_Telephone_break_Name_Location_Telephone etc...

将成为一个数组：

0 => 'Name_Location_Telephone_'
1 => '_Name_Location_Telephone_'
2 => '_Name_Location_Telephone_'
etc...

当您分解这些内容时，第一个会在索引Name处有0，但在索引1处会有所有后续爆炸。

你应该在_break_上爆炸。

如果您已完成任何基本调试，例如var_dump($shops)和var_dump($values)，您就已经看到了事情的变化。

Answer 2

1）你的第一次爆炸会保留一些修剪下划线。

2）您必须使用json_encode方法将数组转换为json数据

您可以做的一个例子

$result = "Name_Location_Telephone_break_Name_Location_Telephone_break_Name_Location_Telephone_break_Name_Location_Telephone_break_";
$shops = explode("_break_",$result);

foreach($shops as $key => $shop) {
    $res["Shop ".$key] = explode('_', $shop);
}

$jsonData = json_encode($res);

Answer 3

这并不是你如何编写foreach的。它与Java不同。结帐：http://php.net/manual/en/control-structures.foreach.php示例，并且从现在开始不要犹豫（thei PHP API非常好）

Answer 4

你几乎接近你所要求的结果。尝试以下

 $shops = explode("_break_",$result);
 $jsonArray = array();
 foreach ($shops as $shop){
     // three elements are same in response no need to worry just explode in array of three elements.
  $value = explode("_", $shop); 
   // assign prepared array or print it according to your business logic.
   $jsonArray[] = array ('name'=>$value[0], 'location'=>$value[1], 'telephone'=>$value[2]); 
 }
 //here you can encode your final multi dimensional array to json string.
echo json_encode($jsonArray);

Answer 5

首次爆炸后，您需要修剪＆＃39; _＆＃39;在$ shops数组中的最后一个字符串。

<?php
    $result = "Name_Location_Telephone_break_Name_Location_Telephone_break_Name_Location_Telephone_break_Name_Location_Telephone";
    $shops = explode("break",$result);
    echo json_encode($shops)."\n";
    $values = array();
    foreach ($shops as $shop){
        $values = explode("_", trim($shop, '_'));
        echo json_encode($values)."\n";
        $name = $values[0];
        $location = $values[1];
        $tel = $values[2];
        echo $name."\n";
    }
?>

结果是，

["Name_Location_Telephone_","_Name_Location_Telephone_","_Name_Location_Telephone_","_Name_Location_Telephone"]
["Name","Location","Telephone"]
Name
["Name","Location","Telephone"]
Name
["Name","Location","Telephone"]
Name
["Name","Location","Telephone"]
Name

Answer 6

它没有用，因为你的第一次爆炸会保留一些修剪下划线。

要么

$shops = explode("_break_",$result);

或

$shops = trim(explode("break",$result), "_");

Answer 7

试试这个：

$result = "Name_Location_Telephone_break_Name_Location_Telephone_break_Name_Location_Telephone_break_Name_Location_Telephone";

$shops = explode("_break_",$result);
$results = array();
$index = 1;

foreach ($shops as $shop) {
    $values = explode("_", $shop);

    $results["Shop $index"] = [
        'name' => $values[0],
        'location' => $values[1],
        'telephone' => $values[2],
    ];

    $index++;
}

print_r($results);

结果是：

Array
(
    [Shop 1] => Array
        (
            [name] => Name
            [location] => Location
            [telephone] => Telephone
        )

    [Shop 2] => Array
        (
            [name] => Name
            [location] => Location
            [telephone] => Telephone
        )

    [Shop 3] => Array
        (
            [name] => Name
            [location] => Location
            [telephone] => Telephone
        )

    [Shop 4] => Array
        (
            [name] => Name
            [location] => Location
            [telephone] => Telephone
        )

)

你有空闲＆＃34; _＆＃34;在explode仅break之后，这就是结果可能出错的原因。

php - 将数组分解为key-＆gt;值数组

7 个答案: