Question

我为我的网站创建了一个STEAM OPENID，但有些错误。我不知道错误是什么..有人可以帮助我......

错误：

Warning: mysqli_query() expects parameter 1 to be mysqli, string given in D:\xampp\htdocs\PTgamersCo\steamid.php on line 69

Warning: mysqli_num_rows() expects parameter 1 to be mysqli_result, null given in D:\xampp\htdocs\PTgamersCo\steamid.php on line 73

Warning: mysqli_query() expects parameter 1 to be mysqli, string given in D:\xampp\htdocs\PTgamersCo\steamid.php on line 76

这是我的数据库连接

$username = "root"; 
$password = ""; 
$host = "localhost"; 
$db = "steam_users";

$sql_steam = mysqli_connect($host, $username, $password, $db);

if (!$sql_steam) {
    echo "Error: Unable to connect to MySQL." . PHP_EOL;
    echo "Debugging errno: " . mysqli_connect_errno() . PHP_EOL;
    echo "Debugging error: " . mysqli_connect_error() . PHP_EOL;
    exit;
}
mysqli_close($sql_steam);

此代码将添加到DB。

foreach ($json_decoded->response->players as $player) 
{
    $sql_fetch_id = "SELECT * FROM users_steam WHERE steamid = $player->steamid";
    $query_id = mysqli_query($db, $sql_fetch_id);

    //$_SESSION['avatar'] = $player->avatar;

    if(mysqli_num_rows($query_id) == 0) {

        $sql_steam = "INSERT INTO users_steam (name, steamid, avatar) VALUES ('$player->personaname', '$player->steamid', '$player->avatar')";
        mysqli_query($db, $sql_steam);
    }
}

Answer 1

所有mysqli_*函数都要求第一个参数为mysqli_connect($host, $username, $password, $db);调用返回的变量。

此外，您需要保持连接处于打开状态才能使用它，因此请删除DBCONNECTION脚本中的mysqli_close($db);

所以修改你的DBCONNECTION到这个

$username = "root"; 
$password = ""; 
$host = "localhost"; 
$dbname = "steam_users";

$db = mysqli_connect($host, $username, $password, $dbname );

if (!$db) {
    echo "Error: Unable to connect to MySQL." . PHP_EOL;
    echo "Debugging errno: " . mysqli_connect_errno() . PHP_EOL;
    echo "Debugging error: " . mysqli_connect_error() . PHP_EOL;
    exit;
}
// Dont close the connection, or you wont be able to use it later
//mysqli_close($db);

您的其他代码将在$db变量

中包含正确的信息

STEAMID OPEN ID错误

1 个答案: