Question

假设我有一个字符串，例如：

string = 'This string 22 is not yet perfect1234 and 123pretty but it can be.'

我想删除任何与混合的数字，例如'perfect1234'和'123pretty'，但不是 '22' ，从我的字符串中得到如下输出：

string = 'This string 22 is not yet perfect and pretty but it can be.'

有没有办法在Python中使用正则表达式或任何其他方法？任何帮助，将不胜感激。谢谢！

Answer 1

s = 'This string 22 is not yet perfect1234 and 123pretty but it can be.'

new_s = ""
for word in s.split(' '):
    if any(char.isdigit() for char in word) and any(c.isalpha() for c in word):
        new_s += ''.join([i for i in word if not i.isdigit()])
    else:
        new_s += word
    new_s += ' '

结果：

'This string 22 is not yet perfect and pretty but it can be.'

Answer 2

如果你想保留自己的数字（不是包含字母字符的单词的一部分），这个正则表达式将完成这项工作（但可能有办法让它更简单）：

import re
pattern = re.compile(r"\d*([^\d\W]+)\d*")
s = "This string is not yet perfect1234 and 123pretty but it can be. 45 is just a number."
pattern.sub(r"\1", s)
'This string is not yet perfect and pretty but it can be. 45 is just a number.'

这里留下了45，因为它不是单词的一部分。

Answer 3

import re
re.sub(r'\d+', '', string)

Answer 4

下面的代码检查每个字符的数字。如果它不是数字，则将字符添加到更正字符串的末尾。

string = 'This string is not yet perfect1234 and 123pretty but it can be.'

CorrectedString = ""
for characters in string:
    if characters.isdigit():
        continue
    CorrectedString += characters

Answer 5

您可以通过简单地加入函数以及无需导入任何内容来尝试此操作

str_var='This string is not yet perfect1234 and 123pretty but it can be.'

str_var = ''.join(x for x in str_var if not x.isdigit())
print str_var

输出：

'This string is not yet perfect and pretty but it can be.'

Answer 6

print(''.join(x for x in strng if not x.isdigit()).replace(' ',' '))

p.s。删除数字后。用单个空格替换双精度空格

输出：

This string is not yet perfect and pretty but it can be.

删除与字符串中的字母混合的数字

6 个答案: