每月总订单的SQL查询

时间:2016-08-09 16:28:37

标签: sql sql-server

我试图在SQL中编写一个查询,计算当前年度每月订单总额(美元金额)。

我的表是这样设置的:

OrderID      OrderTotal       OrderDate
5598745      85.70            2016-07-29
5598744      184.75            2016-07-25
5598743      847.50            2016-06-20
5598742      50.00            2016-06-05

所以我的查询应该显示如下:

June $897.50
July $270.45
etc...

我没有成功地使用它:

SELECT 
  month(OrderDate) AS month_name, 
  SUM(OrderTotal) AS sum_of_month, 
  AVG(SUM(OrderTotal)) OVER () AS avg_sum 
FROM 
  [db].[dbo].[orders] 
WHERE 
  YEAR(OrderDate) = YEAR(GetDate())

4 个答案:

答案 0 :(得分:1)

月份总和你应该使用分组

SELECT month(OrderDate) AS month_name, 
        SUM(OrderTotal) AS sum_of_month
        AVG(OrderTotal) AS AVG_of_month
FROM [db].[dbo].[orders] 
WHERE YEAR(OrderDate) = YEAR(GetDate())
GROUP BY month(OrderDate);

答案 1 :(得分:1)

  

使用DateName()获取月份名称

Declare @Table table (OrderTotal money,OrderDate Date)
Insert into @Table values
(85.70,'2016-07-29'),
(184.75,'2016-07-25'),
(847.50,'2016-06-20'),
(50.00,'2016-06-05')

 Select MonthName=DateName(MM,OrderDate)
       ,Total=sum(OrderTotal)
     From  @Table
     Where Year(OrderDate) = Year(GetDate())
     Group By Month(OrderDate),DateName(MM,OrderDate)
     Order By Month(OrderDate)

返回

MonthName   Total
June        897.50
July        270.45

答案 2 :(得分:0)

试试这可能有效

SELECT 
  month(OrderDate) AS month_name, 
  SUM(OrderTotal) AS sum_of_month, 
  AVG(SUM(OrderTotal)) OVER () AS avg_sum 
FROM 
  [db].[dbo].[orders] 
WHERE 
  YEAR(OrderDate) = YEAR(GetDate())
order by  month(OrderDate)

答案 3 :(得分:0)

这是一个简单的查询,用于计算每月的总和。

select datename(month, dateadd(month, month(OrderDate), 0) - 1) as month_name, 
   sum(OrderTotal) as sum_of_month 
   from Orders
where year(OrderDate) = year(getdate())
group by month(OrderDate)
order by month(OrderDate)

您似乎希望获得所有总和的平均值。我不认为将它呈现在此表中是个好主意。每行将显示相同的数字。相反,我建议单独的查询:

select avg(t.month_sum) from 
    (select sum(OrderTotal) as month_sum from Orders 
     where year(OrderDate) = year(getdate()) 
     group by month(OrderDate)
    ) as t
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