以表格形式过滤显示

时间:2016-08-19 03:03:10

标签: php html mysql css sql

我想制作一个表格形式,使用

中的if语句使用查询过滤显示
import {Injectable} from '@angular/core';
import {CanActivate, ActivatedRouteSnapshot, RouterStateSnapshot} from '@angular/router';
import {Observable} from 'rxjs/Rx';
import {LoginService} from './login/login.service';

@Injectable()
export class AuthGuard implements CanActivate {
    constructor(private loginService: LoginService) {}

    canActivate(route: ActivatedRouteSnapshot, state: RouterStateSnapshot): Observable<boolean> | boolean {
        return this.loginService.signin()
    }
}

这是我的导航栏

if(!$status) die("Failed to select database!");
@$sql = "SELECT * FROM t_pdf Order by  year desc, dotype asc, ref desc ";
if(@$_SESSION['nav']=='DC'){
    @$sql = "SELECT * FROM t_pdf where dotype LIKE '%D.C.%' Order by  year desc, dotype asc, ref desc ";
}

Here is the out

当我点击DC,DO,IC等时,它会改变它的sql并用

编辑它

&#34;从表中选择*,其中control_number类似于&#39;%D.C。%&#39;&#34;

我怎么能改变这里的逻辑?我在这里使用php ....

0 个答案:

没有答案
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