Question

我很困惑如何解析这个xml并转到下一个标签

rss - ＆gt;频道 - ＆gt;项目

像这种结构的xml树，请帮助我完成它。提前谢谢。

<rss>
<channel>
    <item>
        <link> </link>
        <title> </title>
    </item>
</channel>

android java code：

public class RssXmlParser {
private static final String ns = null;
public List<Entry> parse(InputStream in) throws XmlPullParserException, IOException {
    try {
        XmlPullParser parser = Xml.newPullParser();
        parser.setFeature(XmlPullParser.FEATURE_PROCESS_NAMESPACES, false);
        parser.setInput(in, null);
        parser.nextTag();
        return readFeed(parser);
    } finally {
        in.close();
    }
}
private List<Entry> readFeed(XmlPullParser parser) throws XmlPullParserException, IOException {
    List<Entry> entries = new ArrayList<Entry>();

    parser.require(XmlPullParser.START_TAG, ns, "channel");

    while (parser.next() != XmlPullParser.END_TAG) {
        if (parser.getEventType() != XmlPullParser.START_TAG) {
            continue;
        }
        String name = parser.getName();
        if (name.equals("item")) {
            entries.add(readEntry(parser));
        } else {
            skip(parser);
        }
    }
    return entries;
}


public static class Entry {
    public final String url;
    public final String title;

    private Entry(String url,String title) {
        this.url = url;
        this.title=title;
    }
}
private Entry readEntry(XmlPullParser parser) throws XmlPullParserException, IOException {
    parser.require(XmlPullParser.START_TAG, ns, "item");
    String title = null;
    String link = null;
    while (parser.next() != XmlPullParser.END_TAG) {
        if (parser.getEventType() != XmlPullParser.START_TAG) {
            continue;
        }
        String name = parser.getName();
        if (name.equals("title")) {
            title = readTitle(parser);
        } else if (name.equals("link")) {
            link = readLink(parser);
        } else {
            skip(parser);
        }
    }
    return new Entry(link,title);
}
private String readTitle(XmlPullParser parser) throws IOException, XmlPullParserException {
    parser.require(XmlPullParser.START_TAG, ns, "title");
    String title = readText(parser);
    parser.require(XmlPullParser.END_TAG, ns, "title");
    return title;
}
private String readLink(XmlPullParser parser) throws IOException, XmlPullParserException {
    String link = "";
    parser.require(XmlPullParser.START_TAG, ns, "link");
    link = readText(parser);
    parser.require(XmlPullParser.END_TAG, ns, "link");
    return link;
}
private String readText(XmlPullParser parser) throws IOException, XmlPullParserException {
    String result = "";
    if (parser.next() == XmlPullParser.TEXT) {
        result = parser.getText();
        parser.nextTag();
    }
    return result;
}

private void skip(XmlPullParser parser) throws XmlPullParserException, IOException {
    if (parser.getEventType() != XmlPullParser.START_TAG) {
        throw new IllegalStateException();
    }
    int depth = 1;
    while (depth != 0) {
        switch (parser.next()) {
            case XmlPullParser.END_TAG:
                depth--;
                break;
            case XmlPullParser.START_TAG:
                depth++;
                break;
        }
    }
}
}

link is here

Answer 1

在这个解析中重复解析直到事件是结束文档，当事件类型是开始标记然后检查欲望标记从中得到的值示例代码在此处获取what_tagyou_want标记中“名称”属性的值。

MATCH(n)
WHERE n.name CONTAINS 'car'
RETURN n

Answer 2

这里是xml pull解析的完整示例试试这个：

https://androidgarden.wordpress.com/2016/09/02/android-xml-pull-parsing-from-sd-card-assets/

如何在android中解析这个xml文件 - XmlPullParser？

2 个答案: