Question

当我尝试将数据从servlet传递给jsp时，数据传递成功但是，它看起来像是警告，实际上我想在新的jsp页面中显示它。

这是我的servlet和我要显示它的jsp文件，

public void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
    // TODO Auto-generated method stub

    System.out.println("Servlet called!!");
    String feature=request.getParameter("id");  
    PrintWriter out = null;
    Connection conn = null;
    Statement stmt=null;
    ResultSet rs;
    try{
        conn = JBDC.ConnectionFactory.getConnection();

        // Execute SQL query
        stmt = conn.createStatement();
        String sql;
        sql = "SELECT * FROM customers.add_voice where Feature='" +feature+  "'";
        rs = stmt.executeQuery(sql);


        // Extract data from DB
        if(!rs.next()){
            //Do nothing
        }else{
            do{
                String price = rs.getString("Price");
                response.setContentType("text/html");
                request.setAttribute("feature", feature);
                request.setAttribute("price", price);
                request.getRequestDispatcher("/SelectedFeature.jsp").forward(request, response);
            }while(rs.next());
        }

        // Clean-up
        rs.close();
        stmt.close();
        conn.close();
    }catch(SQLException se){
        //Handle errors for JDBC
        se.printStackTrace();
    }catch(Exception e){
        //Handle errors for Class.forName
        e.printStackTrace();
    }finally{
        try{
            if(stmt!=null)
                stmt.close();
        }catch(SQLException se2){
        }
        try{
            if(conn!=null)
                conn.close();
        }catch(SQLException se){
            se.printStackTrace();
        }
    }
}

//在jsp中我正在抓取它

<%=(String)request.getAttribute("feature")%>
<%=(String)request.getAttribute("price")%>

what I mean by alert

//我的jsp文件

<%@ page language="java" contentType="text/html; charset=UTF-8"
    pageEncoding="UTF-8"%>
<!DOCTYPE html>
<html>
<head>
<meta charset="UTF-8">
<META http-equiv="Content-Style-Type" content="text/css">
<script src="javascript/jquery-3.1.0.min.js"></script>
<script src="WebContent/javascript/basic.js"></script>
<script src="javascript/basic.js"></script>
<title>Insert title here</title>
</head>
<body>
    <%=(String)request.getAttribute("feature")%>
    <%=(String)request.getAttribute("price")%>

</body>
</html>

Answer 1

这不是警报，您的JSP文件告诉浏览器输出内容是样式表。

<META http-equiv="Content-Style-Type" content="text/css">

将"text/css"更改为"text/html"，因为您似乎发送的内容是HTML。

虽然在你的评论中你说这是一个AJAX请求，所以你想要发回的东西可能不是HTML，你需要重新考虑使用JSP作为响应，因为AJAX请求通常不使用HTML来处理数据传输。

将数据servlet传递给jsp

1 个答案: