Question

所以我有一个基本的选择下拉框：

      <select class="form-control" name="work_place">
        <option>Work Place 1</option>
        <option>Work Place 2</option>
        <option>Work Place 3</option>
        <option>Work Place 4</option>
      </select>

使用php代码：

$work  = $_POST['work_place'];

如果我想稍后编辑它，回显所选值的最佳方法是什么？

解决感谢＆＃34; help＆＃34;，以下是答案：

      <select class="form-control" name="work_place">
        <option <?php echo ($edit_row["workPlace"] === "Work Place 1")?"selected" : ""; ?> >Work Place 1</option>
        <option <?php echo ($edit_row["workPlace"] === "Work Place 2")?"selected" : ""; ?> >Work Place 2</option>
        <option <?php echo ($edit_row["workPlace"] === "Work Place 3")?"selected" : ""; ?> >Work Place 3</option>
        <option <?php echo ($edit_row["workPlace"] === "Work Place 4")?"selected" : ""; ?> >Work Place 4</option>
      </select>

它回显了所选的下拉选项。

Answer 1

尝试这个

<form action="" method="post"> 
     <select class="form-control" name="work_place">
        <option value="Work Place 1">Work Place 1</option>
        <option value="Work Place 2">Work Place 2</option>
        <option value="Work Place 3">Work Place 3</option>
        <option value="Work Place 4">Work Place 4</option>
      </select>
      <input type="submit" value="go" />
      </form>
      <?php 
      $post = (isset($_POST['work_place'])) ? $_POST['work_place'] : '';
      echo $post;
      ?>

选择框的回声值

1 个答案: