Question

我正在尝试在XML文件上使用XSLT将其转换为另一个XML文件。这是我的XSLT

<xsl:stylesheet version="2.0"
    xmlns:xsl="http://www.w3.org/1999/XSL/Transform" 
    xmlns:og="http://og.com"
    xmlns:xs="http://www.w3.org/2001/XMLSchema"
    xmlns:fn="http://www.w3.org/2005/xpath-functions"
    exclude-result-prefixes="xs fn">
    <xsl:output method="xml" encoding="UTF-8" byte-order-mark="no"
        indent="yes" />

<xsl:template match="@*|node()">
    <xsl:copy><xsl:apply-templates select="@*|node()"/></xsl:copy>
</xsl:template>

<xsl:template match="_source/extension">
    <xsl:for-each select="*">
        <xsl:element name="MT">
            <xsl:attribute name="N" select="name()"/>
            <xsl:attribute name="V" select="."/>
        </xsl:element>
    </xsl:for-each>
</xsl:template>

    <xsl:template match="/">
        <GSP>
            <xsl:attribute name="VER">
                <xsl:value-of select="3.2" />
            </xsl:attribute>
            <xsl:for-each select="root">
                <TM>
                    <xsl:value-of select="(floor(took) div floor(1000))" />
                </TM>

                <RES>
                    <M>
                        <xsl:value-of select="floor(hits/total)" />
                    </M>
                    <xsl:for-each select="hits/hits">
                        <xsl:variable name="var1_resultof_first" as="node()"
                            select="_source" />
                        <R>
                            <xsl:attribute name="N">
                            <xsl:number format="0" level="single" />
                            </xsl:attribute>
                            <U>
                                <xsl:sequence
                                    select="xs:string(xs:anyURI(fn:string($var1_resultof_first/U)))" />
                            </U>
                            <UE>
                                <xsl:sequence
                                    select="xs:string(xs:anyURI(fn:string($var1_resultof_first/UE)))" />
                            </UE>
                            <UD>
                                <xsl:sequence
                                    select="xs:string(xs:anyURI(fn:string($var1_resultof_first/UD)))" />
                            </UD>
                            <T>
                                <xsl:sequence select="fn:string($var1_resultof_first/T)" />
                            </T>
                            <Last-Modified>
                                <xsl:value-of select="substring-before(_source/submitTime,'T')" /> 
                            </Last-Modified>
                            <S>
                                <xsl:for-each select="highlight/newContent">
                                    <xsl:sequence select="fn:string(.)" />
                                </xsl:for-each>
                            </S>

                        </R>
                    </xsl:for-each>
                </RES>
            </xsl:for-each>
        </GSP>
    </xsl:template>
</xsl:stylesheet>

它有两个与

匹配的template.One

<xsl:template match="_source/extension">

和另一个匹配

<xsl:template match="/">

但是当我为输入XML运行这个XSLT时，只在我的XML上应用了上面的模板

 <xsl:template match="/">

未应用其他匹配（_source / match）。我们可以在同一个XSLT中使用多个模板吗？我可能会在这里遗漏一些东西。

Answer 1

当然只有match="/"模板应用于您的XML。它匹配根节点，从不调用任何其他模板，所以没有其他模板被调用的事实不应该是一个惊喜。

要获得更好的结果，请从代码中删除每个<xsl:for-each>，并将其替换为<xsl:apply-templates>和相应的匹配模板。 <xsl:for-each>有其用途，但在您的用例中没有一个出现。

像这样：

<xsl:template match="/">
    <GSP VER="3.2">
        <xsl:apply-templates match="root" />
    </GSP>
<xsl:template>

<xsl:template match="root">
    <TM>
        <!-- floor(1000) is... 1000. Maybe you mean something else? -->
        <xsl:value-of select="floor(took) div floor(1000)" />
    </TM>
    <RES>
        <M><xsl:value-of select="floor(hits/total)" /></M>
        <xsl:apply-templates="hits/hits" />
    </RES>
</xsl:template>

<xsl:template match="hits/hits">
    <R>
        <xsl:attribute name="N">
            <xsl:number format="0" level="single" />
        </xsl:attribute>
        <!-- you could use select="_source/U,_source/UE,_source/UT" here, too -->
        <xsl:apply-templates select="_source/U" mode="URI" />
        <xsl:apply-templates select="_source/UE" mode="URI" />
        <xsl:apply-templates select="_source/UD" mode="URI" />
        <T><xsl:value-of select="_source/T" /></T>
        <Last-Modified>
            <xsl:value-of select="substring-before(_source/submitTime,'T')" /> 
        </Last-Modified>
        <xsl:apply-templates select="highlight/newContent" />
    </R>
</xsl:template>

<xsl:template match="*" mode="URI">
    <xsl:copy>
        <xsl:value-of select="xs:anyURI(.)" />
    </xsl:copy>
</xsl:template>

<xsl:template match="highlight/newContent">
    <S><xsl:value-of select="." /></S>
</xsl:template>

针对做一件事的简短，专注的模板。

使用_source/extension在正确的位置调用<xsl:apply-templates>模板。也从该模板中删除<xsl:for-each>。

阅读What are the differences between 'call-template' and 'apply-templates' in XSL?和For loops vs. apply-templates以及differences between for-each and templates in xsl?以及其他类似文章，了解有关模板在XSLT中如何工作的更多详细信息。

如何在同一个XSLT中使用具有不同匹配的多个模板

1 个答案: