Question

我有DataGrid，绑定到数据库表，我需要在DataGrid中获取所选行的内容，例如，我想在所选行的MessageBox内容中显示

DataGrid的示例：

enter image description here

因此，如果我选择第二行，我的MessageBox必须显示如下内容： 646 Jim Biology 。

Answer 1

您可以使用SelectedItem属性获取当前选定的对象，然后可以将其转换为正确的类型。例如，如果您的DataGrid绑定到Customer个对象的集合，则可以执行此操作：

Customer customer = (Customer)myDataGrid.SelectedItem;

或者，您可以将SelectedItem绑定到源类或ViewModel。

<Grid DataContext="MyViewModel">
    <DataGrid ItemsSource="{Binding Path=Customers}"
              SelectedItem="{Binding Path=SelectedCustomer, Mode=TwoWay}"/>
</Grid>

Answer 2

如果您正在使用MVVM模式，则可以将VM的SelectedRecord属性与DataGrid的SelectedItem绑定，这样您在VM中始终拥有SelectedValue。否则，您应该使用DataGrid的SelectedIndex属性。

Answer 3

public IEnumerable<DataGridRow> GetDataGridRows(DataGrid grid)
{
    var itemsSource = grid.ItemsSource as IEnumerable;
    if (null == itemsSource) yield return null;
    foreach (var item in itemsSource)
    {
        var row = grid.ItemContainerGenerator.ContainerFromItem(item) as DataGridRow;
        if (null != row) yield return row;
    }
}

private void DataGrid_Details_SelectionChanged(object sender, SelectionChangedEventArgs e)
{
    try
    {           
        var row_list = GetDataGridRows(DataGrid_Details);
        foreach (DataGridRow single_row in row_lis)
        {
            if (single_row.IsSelected == true)
            {
                MessageBox.Show("the row no."+single_row .GetIndex ().ToString ()+ " is selected!");
            }
        }

    }
    catch { }
}

Answer 4

在这个DataGrid dg中这非常简单，并且在datagrid中填充了item类，而listblock1是一个基本框架。

private void DataGrid_SelectionChanged(object sender, SelectionChangedEventArgs e)
    {
        try
        {
            var row_list = (Item)dg.SelectedItem;
            listblock1.Content = "You Selected: " + row_list.FirstName + " " + row_list.LastName;
        }
        catch { }

    }
    public class Item
    {
        public string FirstName { get; set; }
        public string LastName { get; set; }
    }

Answer 5

你也可以：

DataRowView row = dataGrid.SelectedItem as DataRowView;
MessageBox.Show(row.Row.ItemArray[1].ToString());

Answer 6

好吧，我会为我提供类似的解决方案。

 private void DataGrid1_SelectionChanged(object sender, SelectionChangedEventArgs e)
        {
            try
            {
                if (DataGrid1.SelectedItem != null)
                {
                    if (DataGrid1.SelectedItem is YouCustomClass)
                    {
                        var row = (YouCustomClass)DataGrid1.SelectedItem;

                        if (row != null)
                        {
                            // Do something...

                            //  ButtonSaveData.IsEnabled = true;

                            //  LabelName.Content = row.Name;

                        }
                    }
                }
            }
            catch (Exception)
            {
            }
        }

Answer 7

private void Fetching_Record_Grid_MouseDoubleClick_1(object sender, MouseButtonEventArgs e)
{
    IInputElement element = e.MouseDevice.DirectlyOver;
    if (element != null && element is FrameworkElement)
    {
        if (((FrameworkElement)element).Parent is DataGridCell)
        {
            var grid = sender as DataGrid;
            if (grid != null && grid.SelectedItems != null && grid.SelectedItems.Count == 1)
            {
                //var rowView = grid.SelectedItem as DataRowView;
                try
                {
                    Station station = (Station)grid.SelectedItem;
                    id_txt.Text =  station.StationID.Trim() ;
                    description_txt.Text =  station.Description.Trim();
                }
                catch
                {

                }
            }
        }
    }
}

Answer 8

在我尝试了Fara的答案之后刚刚发现了这个，但它对我的项目没有用。只需从“数据源”窗口拖动该列，然后将其拖放到“标签”或“文本框”。

Answer 9

使用您的Model类获取从datagrid中选择的行值，例如

        XDocument xmlDoc = XDocument.Load(filepath);

        if (tablet_DG.SelectedValue == null)
        {
            MessageBox.Show("select any record from list..!", "select atleast one record", MessageBoxButton.OKCancel, MessageBoxImage.Warning);
        }
        else
        {
            try
            {
                string tabletID = "";

                 /*here i have used my model class named as TabletMode*/

                var row_list = (TabletModel)tablet_DG.SelectedItem; 
                 tabletID= row_list.TabletID;

                var items = from item in xmlDoc.Descendants("Tablet")
                            where item.Element("TabletID").Value == tabletID
                            select item;

                foreach (var item in items)
                {
                    item.SetElementValue("Instance",row_list.Instance);
                    item.SetElementValue("Database",row_list.Database);
                }

                xmlDoc.Save(filepath);
                MessageBox.Show("Details Updated..!"
                + Environment.NewLine + "TabletId: " +row_list.TabletID + Environment.NewLine
                + "Instance:" + row_list.Instance + Environment.NewLine + "Database:" + row_list.Database, "", MessageBoxButton.YesNoCancel, MessageBoxImage.Information);
            }

            catch (Exception ex)
            {
                MessageBox.Show(ex.StackTrace);
            }
        }

Answer 10

如果我选择第二行 -

 Dim jason As DataRowView


    jason = dg1.SelectedItem

    noteText.Text = jason.Item(0).ToString()

noteText将是646.这是VB，但你明白了。

Answer 11

@Krytox用MVVM回答

    <DataGrid 
        Grid.Column="1" 
        Grid.Row="1"
        Margin="10" Grid.RowSpan="2"
        ItemsSource="{Binding Data_Table}"
        SelectedItem="{Binding Select_Request, Mode=TwoWay}" SelectionChanged="DataGrid_SelectionChanged"/>//The binding



    #region View Model
    private DataRowView select_request;
    public DataRowView Select_Request
    {
        get { return select_request; }
        set
        {
            select_request = value;
            OnPropertyChanged("Select_Request"); //INotifyPropertyChange
            OnSelect_RequestChange();//do stuff
        }
     }

Answer 12

这里有很多答案可能在特定的上下文中有效，但是我只是想获取所选行中第一个单元格的文本值。尽管这里接受的答案对我来说是最接近的答案，但仍然需要创建一个类型并将该行强制转换为该类型。我一直在寻找一个更简单的解决方案，这就是我想出的：

MessageBox.Show(((DataRowView)DataGrid.SelectedItem).Row[0].ToString());

这给了我所选行的第一列。希望这可以帮助其他人。

获取DataGrid WPF中的选定行项

12 个答案: