Question

我在我的一个系统上运行一个命令，它会像这样吐出JSON“漂亮”格式：

[
    {
        "server": "servename1",
        "i.p": 127.0.0.1,
        "domain": "generic",
        "OS": "RHEL",
        "Version": 7.0
    },
    {
        "server": "servename2",
        "i.p": 127.0.0.1,
        "domain": "generic",
        "OS": "RHEL",
        "Version": 7.0
   },
    {
        "server": "servename3",
        "i.p": 127.0.0.1,
        "domain": "generic",
        "OS": "RHEL",
        "Version": 7.0
    }
]

我需要像这样在一个衬里中解析这些段落：

[{"server":"servename1","i.p":127.0.0.1,"domain":"generic","OS":"RHEL","Version":7.0},
{"server":"servename2","i.p":127.0.0.1,"domain":"generic","OS":"RHEL","Version":7.0},
{"server":"servename3","i.p":127.0.0.1,"domain":"generic","OS":"RHEL","Version":7.0},]

最简单的方法是什么？我尝试使用SED和JQ，但无法得到它。

Answer 1

如果您使用换行符分隔的JSON：

，则可以在jq中尝试此操作

$ jq -c ".[]" test.json
{"server":"servename1","i.p":"127.0.0.1","domain":"generic","OS":"RHEL","Version":7}
{"server":"servename2","i.p":"127.0.0.1","domain":"generic","OS":"RHEL","Version":7}
{"server":"servename3","i.p":"127.0.0.1","domain":"generic","OS":"RHEL","Version":7}

请注意，我必须引用您示例中的IP地址，因为您发布的JSON不是有效的JSON。

Answer 2

如果您的输入始终是常规的：

如果这不适合您的实际输入，请编辑您的问题以包含更真实的代表性样本输入。

要跳过]和$ awk '!/^[][]/{ORS=(/},/?RS:""); gsub(/[[:blank:]]+/,""); sub(/}$/,"},\n"); print}' file {"server":"servename1","i.p":127.0.0.1,"domain":"generic","OS":"RHEL","Version":7.0}, {"server":"servename2","i.p":127.0.0.1,"domain":"generic","OS":"RHEL","Version":7.0}, {"server":"servename3","i.p":127.0.0.1,"domain":"generic","OS":"RHEL","Version":7.0},行：

{{1}}

将JSON“漂亮”格式解析为一个班轮

2 个答案: