Question

我有一个这样的数组：

Array
(
    [0] => Array
        (
            [score] => 80
            [seen] => 1
        )

    [1] => Array
        (
            [score] => 4
            [seen] => 1
        )
    [2] => Array
        (
            [score] => 4
            [seen] => 0
        )
    [3] => Array
        (
            [score] => 4
            [seen] => 0
        )
    [4] => Array
        (
            [score] => 4
            [seen] => 0
        )
)

我需要检查是否有[seen] = 1？

if ( /* ??? */ ){
    echo "Yes, at least one of [seen] keys is 1";
} else {
    echo "No, all [seen] keys are 0";
}

我该如何创造这种条件？

Answer 1

使用简单的foreach循环可以帮助您

foreach ($array as $arr) {
 if ($arr['seen']==1){
   echo 'SEEN';
  }
}

Answer 2

>>> import numpy
>>> array = numpy.array([49, 51, 53, 56])
>>> array - 13
array([36, 38, 40, 43])

如果[see]键中至少有一个是1

，则

$seen = false; foreach($my_array as $el){ if($el['seen']){ $seen = true; break; } }为真如果所有[see]键都为0

，则

$seen为false

Answer 3

采用功能方法，您可以使用测试For Each s in Sheets Select Case s.Name Case "Orange", "Apple", "Broccoli", "Cheese" ActiveWorkbook.SaveAs strPath Exit For End Select Next的函数过滤数组。然后，如果结果数组非空，您知道有些元素具有'seen' == 1值。

'seen' == 1

当然，一旦找到单个<?php $ar = array( 0 => array( 'score' => 80, 'seen' => 1 ), 1 => array( 'score' => 4, 'seen' => 1 ), 2 => array( 'score' => 4, 'seen' => 0 ) ); if ( array_filter($ar, function($x) { return $x['seen'] == 1; }) ){ echo "Yes, at least one of [seen] keys is 1"; } else { echo "No, all [seen] keys are 0"; } ?>元素，此方法的效率低于突破循环的方法。但它确实在条件中给你一个表达式。

Answer 4

$seen = in_array(1, array_column($array, 'seen'));

文档：

如何检查数组的嵌套项的值？

4 个答案: