gdb堆栈跟踪中的第二列是什么意思?

时间:2010-10-13 18:17:55

标签: gdb stack-trace

我有一个如下所示的堆栈跟踪:

#3  0x00007fffde86c206 in GetMedia (p_ml=0xb91560, id=<value optimized out>, select=ML_MEDIA, reload=<value optimized out>) at ../../../modules/media_library/sql_media_library.c:1170
#4  0x00007fffde86a7d0 in GetInputItemFromMedia (p_ml=0xb91560, i_media=12276000) at ../../../modules/media_library/sql_media_library.c:1204
#5  0x00007ffff6765eab in ml_CreateInputItem (this=0x7784f0) at ../../../../include/vlc_media_library.h:887
#6  MLModel::popupInfo (this=0x7784f0) at ../../../../modules/gui/qt4/components/playlist/media_library/ml_model.cpp:528
#7  0x00007ffff67a7204 in MLModel::qt_metacall (this=0x7784f0, _c=<value optimized out>, _id=17710, _a=<value optimized out>) at components/playlist/media_library/ml_model.moc.cpp:79
#8  0x00007ffff4ec8e3f in QMetaObject::activate(QObject*, QMetaObject const*, int, void**) () from /usr/lib/libQtCore.so.4

我想知道第二列表示。此外,缺乏什么意味着什么?可以看出,帧#6没有这个地址,我相信我的问题(一个段错误)是由于相关的事情引起的。

1 个答案:

答案 0 :(得分:2)

该列包含从上面的被调用函数到该行上的调用函数的返回地址。它的缺乏可能意味着函数被内联。