Question

我创建了两个if语句进入链表，并检查有多少数字高于平均值，并查看有多少低于平均值。当我按照我的理解运行程序时，if语句只计算一个数字。此外，当程序运行时，只调用其中一个if语句，而不是两者。也许我忽略了什么？

double CalAverage (NewNumber *start){

int res;
double average = 0;
double total = 0;
int n = 1;
int x = 1;
int y = 1; 

/*if (res != 1){
    fprintf(stderr, "Something bad happened in CalAverage()\n");
    return add;
}*/
while (start->next){
    average += start->newNum;
    start = start->next;
    ++n;
}
average += start->newNum;
total = average/n;
if(total < start->newNum){
        ++x;
        printf("Numbers greater than average: %d\n",x);
    }else if(total > start->newNum){
        ++y;
        printf("Numbers less than average: %d\n", y);
    }
printf("The average is: %lf\n",total);
return total; 
return x;
return y;

}

Answer 1

首先，通过在while循环中覆盖它，您将丢失指向列表开头的指针。在开始循环之前将它复制到一边。

第二，将if语句放在另一个循环中（在重新指定列表的开头之后）以计算低于/高于平均值。

double CalAverage (NewNumber *start){

    double average = 0;
    double sum = 0;
    int n = 0;
    int x = 0;
    int y = 0; 

    NewNumber *temp = start;

    while (temp){
        sum += temp->newNum;
        temp = temp->next;
        ++n;
    }

    average = sum / n;

    temp = start;

    while (temp){

        if(average < temp->newNum){
            ++x;
        }else if(average > temp->newNum){
            ++y;
        }

        temp = temp->next;
    }

    printf("The average is: %lf\n",average);
    printf("Numbers greater than average: %d\n",x);
    printf("Numbers less than average: %d\n", y);
    return average; 
}

Answer 2

if语句不在while循环中，因此函数启动，while循环完成，然后只调用一个if语句，因为它是if，elseif

＆＃39; CalAverage＆＃39;中if语句的问题功能

2 个答案: