Question

如何从以下列表中删除86.1和90.1（或86.2和90.2）等数字？

86.1      86.2       90.1      90.2

Answer 1

定义阈值，迭代已排序的数字并将数字加在阈值内：

numbers = [86.1, 86.2, 90.1,90.2]

threshold = 1
numbers = iter(numbers)
amount = last = next(numbers)
count = 1
result = []
for number in sorted(numbers):
    if number - last > threshold:
        result.append(amount/count)
        amount = count = 0
    amount += number
    count += 1
    last = number

result.append（量/计数）

Answer 2

试试这个：

base = [86.1, 86.2, 90.1, 90.2]
# remove = [86.2, 90.2]
remove = [86.1, 90.1]

new_list = [item for item in base if item not in remove]
print(new_list)

在Stack Overflow帖子 Remove list from list in Python 中，您有更多信息。

Answer 3

inputList=[86.1, 86.2, 90.1, 90.2]

tolerance=1.0
out=[]
for num in inputList:
    if all([abs(num-outAlready)>tolerance for outAlready in out]):
        out.append(num)

print out

删除列表中的类似数字

3 个答案: