在我的JSF应用程序中,我有一个@WebFilter,我想在页面转发时获取目标页面的URI。这可能吗?
@WebFilter(servletNames={"Faces Servlet"})
public class MyFilter implements Filter {
@Override
public void doFilter(ServletRequest request, ServletResponse response, FilterChain chain) throws IOException, ServletException {
HttpServletRequest httpReq = (HttpServletRequest) request;
HttpServletResponse httpRes = (HttpServletResponse) response;
// here, can I know the URI?
chain.doFilter(request, response);
}
@Override
public void destroy() {}
@Override
public void init(FilterConfig arg0) throws ServletException {}
}
由于