Question

我正在使用CodeIgniter。在我的Controller文件中，我有一个包含数组的JSON（由于调用了不同的API＆＃39;）

{
    "Specialities": [{
        "SpecialityID": 1,
        "SpecialityName": "Eye Doctor"
    },{
        "SpecialityID": 2,
        "SpecialityName": "Chiropractor"
    },{
        "SpecialityID": 3,
        "SpecialityName": "Primary Care Doctor"
    }] 
}

在控制器中，我写了

echo $response[0];

使用这行代码，我可以轻松地遍历jquery中的json对象：

$.ajax({
    type: 'GET',
    url: 'http://localhost/rest_project/main/res',
    dataType: 'JSON',
    crossDomain: true,
    xhrFields: { withCredentials: true },
    success: function (data){
        $.each(data.Specialities,function(key,value){
            console.log(value.SpecialityName);
        });
    }  
});

但如果我传递数组：

echo json_encode($response);

然后我无法得到结果：

$.ajax({
    type: 'GET',
    url: 'http://localhost/rest_project/main/res',
    dataType: 'JSON',
    crossDomain: true,
    xhrFields: { withCredentials: true },
    success: function (data){
        $.each(data[0].Specialities,function(key,value){
            console.log(value.SpecialityName);
        });
    }
});

有人能帮助我吗？

Answer 1

您的jsonObject似乎不是数组，而each仅适用于数组。

//Check if your jsonObject is array, if not then make it.
if (!$.isArray(jsonObject)) {
    jsonObject = [jsonObject];
}

$.each(jsonObject, function(key, value){
  console.log("FULL NAME " + value.FullName);
});

＆＃13;

var data = {
    "Specialities": [{
        "SpecialityID": 1,
        "SpecialityName": "Eye Doctor"
    },{
        "SpecialityID": 2,
        "SpecialityName": "Chiropractor"
    },{
        "SpecialityID": 3,
        "SpecialityName": "Primary Care Doctor"
    }] 
};
//Convert your jsonObject to array for each
if (!$.isArray(data)) {
    data = [data];
}
$.each(data[0].Specialities,function(key,value){
   console.log(value.SpecialityName);
});

＆＃13;

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

＆＃13;

在jQuery中迭代json对象数组

1 个答案: