Question

我有以下为我生成数据的功能：

 function get_project_time() {
        $name;
        $desc;
        $values;
        $to;
        $from;
        $sql = $this->db->query("Select * from tbl_project")->result();
        foreach ($sql as $value) {

            $name = $value->project_name;
            $desc = $value->project_status;
            $start_date = $value->start_date;
            $end_date = $value->end_date;
            $unix_start_date = strtotime($start_date);
            $unix_end_date = strtotime($end_date);
            $to = "Date($unix_start_date)/";
            $from = "Date($unix_end_date)/";
            $e = new stdClass();
            $f = new stdClass();
            $e->name = $name;
            $e->desc = $desc;
            $f->to = $to;
            $f->from = $from;
            $e->values = array($f);

            echo json_encode(array($e));
        }
    }

json输出以下列格式显示：

[{"name":"e-Campus and eLearning Project","desc":"in_progress","values":[{"to":"\/Date(1473627600)\/","from":"\/Date(1480626000)\/"}]}][{"name":"BloodLink Training Project","desc":"in_progress","values":[{"to":"\/Date(1474405200)\/","from":"\/Date(1475010000)\/"}]}][{"name":"Test Project","desc":"","values":[{"to":"\/Date(1474405200)\/","from":"\/Date(1475182800)\/"}]}]

我想清理数据，以便得到类似的内容：

[{"name":"e-Campus and eLearning Project","desc":"in_progress","values":[{"to":"/Date(1473627600)/","from":"/Date(1480626000)/"}]}][{"name":"BloodLink Training Project","desc":"in_progress","values":[{"to":"/Date(1474405200)/","from":"/Date(1475010000)/"}]}][{"name":"Test Project","desc":"","values":[{"to":"/Date(1474405200)/","from":"/Date(1475182800)/"}]}]

请告知我如何清理json数据？

Answer 1

大部分代码都是冗余/无用的。你可以琐碎地拯救自己有类似这样的行：

$sql = "SELECT project_name AS name, ... UNIX_TIMESTAMP(end_date) AS end_date etc...";

while($row = fetch()) {
   $array[] = $row;
}

echo json_encode($array);

构建一个对象，只是为了将它类型化为一个数组，这完全是浪费和混乱。如果你想要一个数组，那么构建一个数组。做了“给我一个带有额外生菜的bigmac”，然后将它转换成鱼片。

清理Json URL数据

1 个答案: