Question

我试图使用这样的POST命令：

http://123.456.78.9/Dev/SignIn?Username=email%40google.edu&Password=thePassword

在我的Android应用中，我已经查看了像HTTPConnection这样的内容，但我仍然不确定拨打电话的最佳方式是什么，我需要包含多个密钥和值

我现在正在尝试这个：

                URl url = new URL("http://123.456.78.9/Dev/SignIn?");     
                HttpsURLConnection conn = (HttpsURLConnection) url.openConnection();
                conn.setReadTimeout(10000);
                conn.setConnectTimeout(15000);
                conn.setRequestMethod("POST");
                conn.setDoInput(true);
                conn.setDoOutput(true);

                List<NameValuePair> params = new ArrayList<NameValuePair>();
                params.add(new BasicNameValuePair("email", emailText));
                params.add(new BasicNameValuePair("Password", passwordText));
                OutputStream os = conn.getOutputStream();
                BufferedWriter writer = new BufferedWriter(new OutputStreamWriter(os, "UTF-8"));
                writer.write(getQuery(params));
                writer.flush();
                writer.close();
                os.close();

这会完成这项工作吗？如果我要使用这种方法，如何获得响应呢？

Answer 1

您可以使用Android Asynchronous Http Client library：

final AsyncHttpClient asyncHttpClient=new AsyncHttpClient();
    //Add Parameter
    RequestParams requestParams=new RequestParams();
    requestParams.put("email", emailText);
    requestParams.put("Password", passwordText);

    //Chose one from two method in below

    //send with get method
    asyncHttpClient.get("http://123.456.78.9/Dev/SignIn", requestParams, new TextHttpResponseHandler() {
        @Override
        public void onFailure(int statusCode, Header[] headers, String responseString, Throwable throwable) {

        }

        @Override
        public void onSuccess(int statusCode, Header[] headers, String responseString) {
            System.out.println(responseString);
        }
    });

    //send with post method
    asyncHttpClient.post("http://123.456.78.9/Dev/SignIn", requestParams, new TextHttpResponseHandler() {
        @Override
        public void onFailure(int statusCode, Header[] headers, String responseString, Throwable throwable) {

        }

        @Override
        public void onSuccess(int statusCode, Header[] headers, String responseString) {
            System.out.println(responseString);
        }
    });

但你必须在你的gradle上添加这个库

compile 'com.loopj.android:android-async-http:1.4.9'

带有HTTP Url请求的Android POST

1 个答案: